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castortr0y [4]
3 years ago
13

Can somebody help with my 2 way table assignments..? i know some of you will take this as a fre.e points question and i don't re

ally care LOL.. just want some help.
Mathematics
1 answer:
pishuonlain [190]3 years ago
6 0

Answer:

what is the question

Step-by-step explanation:

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Solve the equation. Check your solution.<br><br> -6+a=-2
lukranit [14]
The answer is:
a=6-2

a=4
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4 years ago
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-7x + 2y = -5<br> y = -7x + 8<br> explain how please
Fiesta28 [93]

Answer:

x = 1 and y =1

Step-by-step explanation:

y = -7x + 8

sub into other eq

-7x + 2(-7x + 8) = -5

-7x - 14x + 16 = -5

-21x = -21

x - 1

y = -7(1) + 8

y = 1

7 0
3 years ago
Antonio used 16 1/3 cups of flour to make banana bread.
Volgvan

Answer: Option 1

Step-by-step explanation:

2 1/3 times the number of times it is baked will equal 16 1/3. the equation is also the same as 16 1/3 divided by 2 1/3 = n. Hope this helps:)

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3 years ago
Simplify 56/10 or reduce
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The improper fraction is 28/5. The mixed number is 5 3/5
4 0
3 years ago
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Find a positive number for which the sum of it and its reciprocal is the smallest​ (least) possible. Let x be the number and let
Allisa [31]

Answer:

S(x) = x + \frac{1}{x} --- Objective function

Interval = \{x:x=1\}

Step-by-step explanation:

Given

Represent the number with x

The required sum can be represented as:

x + \frac{1}{x}

Hence, the objective function is:

S(x) = x + \frac{1}{x}

To get the the interval, we start by differentiating w.r.t x

<em>Using first principle, this gives:</em>

S'(x) = 1 - \frac{1}{x^2}

Equate S'(x) to 0 in order to solve for x

0 = 1 - \frac{1}{x^2}

Subtract 1 from both sides

0 -1 = 1 -1 - \frac{1}{x^2}

-1 = - \frac{1}{x^2}

Multiply both sides by -1

1 = \frac{1}{x^2}

Cross Multiply

x^2 * 1 = 1

x^2  = 1

Take positive square root of both sides because x is positive

\sqrt{x^2} = \sqrt{1

x = 1

Representing x using interval notation, we have

Interval = \{x:x=1\}

To get the smallest sum, we substitute 1 for x in S(x) = x + \frac{1}{x}

S(1) = 1 + \frac{1}{1}

S(1) = 1 + 1

S(1) = 2

<em>Hence, the smallest sum is 2</em>

3 0
3 years ago
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