Answer:
<em>Rate of Pratap in still water is 4.5 miles/hour and rate of current is 0.5 miles/hour.</em>
Step-by-step explanation:
Pratap Puri rowed 10 miles down a river in 2 hours, but the return trip took him 2.5 hours.
We know that, 
So, the <u>speed of Pratap with the current</u> will be:
miles/hour
and the <u>speed of Pratap against the current</u> will be:
miles/hour.
Suppose, the rate of Pratap in still water is
and the rate of current is
.
So, the equations will be........

Adding equation (1) and (2) , we will get......

Now, plugging this
into equation (1), we will get.....

Thus, Pratap can row at 4.5 miles per hour in still water and the rate of the current is 0.5 miles/hour.
Answer:
84,000,108
Step-by-step explanation:
Answer:
$3.98(estimated)
Step-by-step explanation:
3c (cake) + 2(2c - 11) (bread) = 5.87
3c + 4c - 22 = 5.87
7c - 22 = 5.87
7c = 5.87 + 22
7c = 27.87
c = 3.98
Answer: 105 couple tickets and 40 individual tickets
For this I will use the "Graphing Method"
First, we need to set up two equations.
-> Let x be the number of couple tickets.
-> Let y be the number of individual tickets.
-> It is "2x" because a couple means two.
$12x + $8y = $1,580
2x + y = 250
Next, we will graph this.
-> The point at which the two lines intersect is our solution.
-> See attached.
-> x = 105, so 105 couple tickets
-> y = 40, so 40 individual tickets
Have a nice day!
I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly.
- Heather