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Butoxors [25]
3 years ago
8

6= 24-6a what is a.......................

Mathematics
2 answers:
AnnyKZ [126]3 years ago
3 0

Answer:

3

Step-by-step explanation:

6=24-6a

6a=24-6

6a^6=18^6

a=3

FrozenT [24]3 years ago
3 0

Answer:

3

Step-by-step explanation:

6 =24 - 6a

6 - 24 =-6a

-18 =-6a

a=18 :6

a=3

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State the value of the discriminant for the equation,<br> 3x^2 + 7x + 3 = 0
Irina-Kira [14]

Answer: 13

Step-by-step explanation:

If you remember the quadratic equation formula;

x=\frac{-b\frac{+}{}\sqrt{b^2-4ac}  }{2a}

You can easily extract what is under the root to find the discriminant.

b^2-4ac=?\\

a = 3

b = 7

c = 3

(7)^2-4(3)(3)\\49-36=13

7 0
3 years ago
Using the formula r=d/t where d is the distance in miles, r is the rate and t is the time in hours at which rate must you travel
valentina_108 [34]

r =  \frac{337.5}{4.5}  \\ r = 75
the answer is c-75mph
6 0
3 years ago
Read 2 more answers
Mary Sue and Betty have 603 necklaces altogether. Mary Sue has 115 more necklaces than Betty. How many necklaces does Betty have
Blizzard [7]

Let Mary Sue have m necklaces and Betty have b necklaces.

And they have 603 necklaces altogether, that is

m + b =603

And Mary Sue has 115 more necklaces than Betty, that is

m=b +115

Substituting this value in first equation we will get

b+115+b=603

Subtracting 115

2b= 488

b= 244

So Betty have 244 necklaces .

6 0
3 years ago
A particular variety of watermelon weighs on average 20.4 pounds with a standard deviation of 1.23 pounds. Consider the sample m
love history [14]

Answer:

a) The expected value of the sample mean weight is 20.4 pounds.

b)The standard deviation of the sample mean weight is 0.123.

c) There is a 14.46% probability the sample mean weight will be less than 20.27.

d) This value is c = 20.6153.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation \frac{\sigma}{\sqrt{n}}.

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

A particular variety of watermelon weighs on average 20.4 pounds with a standard deviation of 1.23 pounds. This means that \mu = 20.4, \sigma = 1.23

Consider the sample mean weight of 100 watermelons of this variety. This means that n = 100.

a. What is the expected value of the sample mean weight? Give an exact answer.

By the Central Limit Theorem, it is the same as the mean of the population. So the expected value of the sample mean weight is 20.4 pounds.

b. What is the standard deviation of the sample mean weight? Give your answer to four decimal places.

By the Central Limit Theorem, that is:

s = \frac{\sigma}{\sqrt{n}} = \frac{1.23}{\sqrt{100}} = 0.123

The standard deviation of the sample mean weight is 0.123.

c. What is the approximate probability the sample mean weight will be less than 20.27?

This is the pvalue of Z when X = 20.27.

Since we are working with the sample mean, we use s instead of \sigma in the Z score formula

Z = \frac{X - \mu}{s}

Z = \frac{20.27 - 20.4}{0.123}

Z = -1.06

Z = -1.06 has a pvalue of 0.1446.

This means that there is a 14.46% probability the sample mean weight will be less than 20.27.

d. What is the value c such that the approximate probability the sample mean will be less than c is 0.96?

This is the value of X = c that is in the 96th percentile, that is, it's Z score has a pvalue 0.96.

So we use Z = 1.75

Z = \frac{X - \mu}{s}

1.75 = \frac{c - 20.4}{0.123}

c - 20.4 = 0.123*1.75

c = 20.6153

This value is c = 20.6153.

6 0
2 years ago
Solve - 2/5x is less than or equal to 20
sashaice [31]

Answer:

x is less than or equal to 0

Step-by-step explanation:

- you need to multiply both sides of the inequality by 5/2

- then you reduce the numbers with the greatest common factor 5

- then you reduce the numbers with the greatest common factor 2

- any expression multiplied by 0 equals 0

- so you get x is less than or equal to 0

^^^ hope this helps! :)

8 0
3 years ago
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