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Temka [501]
3 years ago
5

On a school spirit day 257 students wore gold or black, 34 wore both gold and black, and 178 wore black. How many students wore

only gold?
(Proof not needed, only LEGIT answers only please and thx)

Mathematics
2 answers:
barxatty [35]3 years ago
8 0
The answer is A hope this helps
pentagon [3]3 years ago
7 0

Answer:

2 possible answers

Step-by-step explanation:

Assumption: 178 wore black (that means some may wear gold + black aka as long as they wore abit of black, it's counted):

since there are 257 students and 34 wore both gold and black, and 178 wore black, the number of students who wore only black = 178 - 34 = 144

no of students who wore only gold = 257 - 144 - 34 = 79

Assumption: 178 students wore ONLY black:

no of students who wore only gold: 257 - 178 - 34 = 45

Topic: Set theory

If you like to venture further, feel free to check out my insta (learntionary). It would be best if you could give it a follow. I'll be constantly posting math tips and notes! Thanks!

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The University of Washington claims that it graduates 85% of its basketball players. An NCAA investigation about the graduation
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Probabilities are used to determine the chances of events

The given parameters are:

  • Sample size: n = 20
  • Proportion: p = 85%

<h3>(a) What is the probability that 11 out of the 20 would graduate? </h3>

Using the binomial probability formula, we have:

P(X = x) = ^nC_x p^x(1 - p)^{n -x}

So, the equation becomes

P(x = 11) = ^{20}C_{11} \times (85\%)^{11} \times (1 - 85\%)^{20 -11}    

This gives

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Express as percentage

P(x = 11) = 0.11\%

Hence, the probability that 11 out of the 20 would graduate is 0.11%

<h3>(b) To what extent do you think the university’s claim is true?</h3>

The probability 0.11% is less than 50%.

Hence, the extent that the university’s claim is true is very low

<h3>(c) What is the probability that all  20 would graduate? </h3>

Using the binomial probability formula, we have:

P(X = x) = ^nC_x p^x(1 - p)^{n -x}

So, the equation becomes

P(x = 20) = ^{20}C_{20} \times (85\%)^{20} \times (1 - 85\%)^{20 -20}    

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P(x = 20) = 1 \times (0.85)^{20} \times (0.15\%)^0

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Express as percentage

P(x = 20) = 3.88\%

Hence, the probability that all 20 would graduate is 3.88%

<h3>(d) The mean and the standard deviation</h3>

The mean is calculated as:

\mu = np

So, we have:

\mu = 20 \times 85\%

\mu = 17

The standard deviation is calculated as:

\sigma = np(1 - p)

So, we have:

\sigma = 20 \times 85\% \times (1 - 85\%)

\sigma = 20 \times 0.85 \times 0.15

\sigma = 2.55

Hence, the mean and the standard deviation are 17 and 2.55, respectively.

Read more about probabilities at:

brainly.com/question/15246027

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