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DochEvi [55]
3 years ago
7

I need help with a problem help pls

Mathematics
2 answers:
Viktor [21]3 years ago
6 0
There are 2 circular bases: A = π r²
A = π (3)²
   = 9 π

There is one lateral face that is a rectangle: A = L x W
In this instance, the length equals the perimeter of the circle: L = 2 π r
A = 2 π (3) x 7
   = 42 π

Surface Area = 2(9 π) + 42 π
                       = 18 π + 42 π
                       = 60 π
                       ≈ 188

Answer: D
Tcecarenko [31]3 years ago
4 0
2 π x 3 x 7 + π x 3^2 x2= 60 π= 188
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The computer that controls a bank's automatic teller machine crashes a mean of 0.6 times per day. What is the probability that,
professor190 [17]

Answer:

0.2103 = 21.03% probability that, in any seven-day week, the computer will crash less than 3 times.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given interval.

Mean of 0.6 times a day

7 day week, so \mu = 7*0.6 = 4.2

What is the probability that, in any seven-day week, the computer will crash less than 3 times? Round your answer to four decimal places.

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)

In which

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-4.2}*(4.2)^{0}}{(0)!} = 0.0150

P(X = 1) = \frac{e^{-4.2}*(4.2)^{1}}{(1)!} = 0.0630

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So

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0150 + 0.0630 + 0.1323 = 0.2103

0.2103 = 21.03% probability that, in any seven-day week, the computer will crash less than 3 times.

3 0
3 years ago
Math:<br> Please help me. I don’t understand. Thank you for your time.
GuDViN [60]
I Believe it’s 1,890
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Answer:

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Step-by-step explanation:

Given

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Answer:

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Step-by-step explanation:

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