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xxMikexx [17]
3 years ago
5

30p+2can you please answer ​

Mathematics
1 answer:
yanalaym [24]3 years ago
3 0

Answer:

2(15p+1)

Step-by-step explanation:

hope this helps

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Someone please help me with #28 and #30 I got myself super confused.
bogdanovich [222]

<u><em>Question 28:</em></u>

S-2\pi r^2=2\pi rh                     Subtract 2\pi r^2 on both sides

\frac{S-2\pi r^2}{2\pi r} =h         Divide 2\pi r on both sides

<u><em>*(Answer)*=</em></u>  \frac{S-2\pi r^2}{2\pi r} =h


<u><em>Question 30:</em></u>

a*t=v_{1}+v_{0}                  Multiply t on both sides

a*t+v_{0} =v_{1}                 Subtract v_{0} on both sides

<u><em>*(Answer)*=</em></u> a*t+v_{0} =v_{1}

Hope This Helps

BangtanBoyScouts

4 0
4 years ago
Cyclic quadrilateral.
ad-work [718]
What do you mean, you need more information in your queston p,ease try to ask it again, it makes no Sence
5 0
4 years ago
Read 2 more answers
3/4(x+5 1/2) = 5/8<br><br> Distributive Property <br><br> Brainly
Talja [164]

Answer:

x = - \frac{14}{3}

Step-by-step explanation:

Given

\frac{3}{4} (x + 5 \frac{1}{2} ) = \frac{5}{8}

Multiply both sides by 8 to clear the fractions

6(x + 5 \frac{1}{2} ) = 5 ← distribute parenthesis on left side

6x + 33 = 5 ( subtract 33 from both sides )

6x = - 28 ( divide both sides by 6 )

x = \frac{-28}{6} = - \frac{14}{3}

3 0
3 years ago
In a survey sample of 83 respondents, the mean number of hours worked per week is 39.04, with a standard deviation of 11.51. Cal
soldier1979 [14.2K]

Given that,

Sample size= 83

Mean number= 39.04

Standard deviation= 11.51

We know the critical t-value for  95% confidence interval which is equal to 1.989.

We also know the formula for confidence interval,

CI=( mean number - critical t-value*standard deviation/(sample size)^(1/2), mean number + critical t-value*standard deviation/(sample size)^(1/2))

So, we have

CI= (39.04 - 1.989*11.51/83^(1/2), 39.04 + 1.989*11.51/83^(1/2)

CI= (39.04 - 2.513,39.04 + 2.513)

CI= (36.527,41.553)

Therefore, 95% confidence interval for these data is (36.527,41.553), and this result interpret that the true value for this survey sample lie in the interval (36.527,41.553).

8 0
3 years ago
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Can someone help me with a question i will give brainlyest
Ira Lisetskai [31]

Answer:

what is the question

5 0
3 years ago
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