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gregori [183]
3 years ago
8

The measures of the angles in triangle UVW are shown in the diagram below.

Mathematics
1 answer:
Mamont248 [21]3 years ago
3 0

Answer:

(B) 39°

Step-by-step explanation:

30° + 24° + (3x -9°) = 180°

3x = 180° - 30° - 24° + 9°

3x = 117°|:3

x = 39°

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Mars has m moons. The number of moons of Pluto is one more than twice the number of moons of Mars. The number of moons of Neptun
tigry1 [53]

Answer:

Neptune has 2 more than 6 times the number of moons on mars

Explanation:

neptune = 6m+2

mars has 'm' moons

pluto has one more than twice that of mars, = 2m+1

neptune is one less than thrice of pluto

= 3(2m+1) -1

= 6m+3 -1

= 6m+2

6 0
2 years ago
Consider the table below that represents a quadratic function.
zlopas [31]
It would be -1/2 because the formula to find slope (rate of change) is (y2-y1)/(x2-x1) and in this case it would be (4.5-2)/(-3--2) which simplifies to (2.5)/(-5) which is -1/2
6 0
3 years ago
PLEASE HELP!!!!! What are the values of a and b? -7(x+3)=ax+b
Artist 52 [7]

Step-by-step explanation:

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3 0
3 years ago
Anu
bija089 [108]

Answer:

Circumference of Circle B=19.625cm

Step-by-step explanation:

The circumference formula is: 2pie(r) = pie(d)

We have diameter of the first circle which is 6. Now, because the diameter of second circle is 25% greater than this,

Hence, we add 25% in 6:

6+25/100 =6+0.25=6.25 cm

Therefore, we have diameter of 6.25 for circle B.

Now, we need to find the circumference of the Circle A.

circumference= pie(d) = pie(6)= 3.14times6= 18.84

Now use the proportional reasoning to find Circumference of Circle B:

circumference of Circle A/diameter Circle A = circumference of Circle B/diameter Circle B

18.84/6=circumference of Circle B/6.25

Cross multiply and divide:

(18.84times6.25)/6 = Circumference of Circle B

Solve:

Circumference of Circle B=19.625cm

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7 0
3 years ago
In the illustration below, the three cube-shaped tanks are identical. The spheres in any given tank
fredd [130]

Answer:

1) Volume occupied by the spheres are equal therefore the three tanks contains the same volume of water

2) Amount \ of \, water \ remaining \ in \, the \ tank \ is \  \frac{x^3(6-\pi) }{6}

Step-by-step explanation:

1) Here we have;

First tank A

Volume of tank = x³

The  volume of the sphere = \frac{4}{3} \pi r^3

However, the diameter of the sphere = x therefore;

r = x/2 and the volume of the sphere is thus;

volume of the sphere = \frac{4}{3} \pi \frac{x^3}{8}= \frac{1}{6} \pi x^3

For tank B

Volume of tank = x³

The  volume of the spheres = 8 \times \frac{4}{3} \pi r^3

However, the diameter of the spheres 2·D = x therefore;

r = x/4 and the volume of the sphere is thus;

volume of the spheres = 8 \times \frac{4}{3} \pi (\frac{x}{4})^3= \frac{x^3 \times \pi }{6}

For tank C

Volume of tank = x³

The  volume of the spheres = 64 \times \frac{4}{3} \pi r^3

However, the diameter of the spheres 4·D = x therefore;

r = x/8 and the volume of the sphere is thus;

volume of the spheres = 64 \times \frac{4}{3} \pi (\frac{x}{8})^3= \frac{x^3 \times \pi }{6}

Volume occupied by the spheres are equal therefore the three tanks contains the same volume of water

2) For the 4th tank, we have;

number of spheres on side of the tank, n is given thus;

n³ = 512

∴ n = ∛512 = 8

Hence we have;

Volume of tank = x³

The  volume of the spheres = 512 \times \frac{4}{3} \pi r^3

However, the diameter of the spheres 8·D = x therefore;

r = x/16 and the volume of the sphere is thus;

volume of the spheres = 512\times \frac{4}{3} \pi (\frac{x}{16})^3= \frac{x^3 \times \pi }{6}

Amount of water remaining in the tank is given by the following expression;

Amount of water remaining in the tank = Volume of tank - volume of spheres

Amount of water remaining in the tank = x^3 - \frac{x^3 \times \pi }{6} = \frac{x^3(6-\pi) }{6}

Amount \ of \ water \, remaining \, in \, the \ tank =  \frac{x^3(6-\pi) }{6}.

5 0
3 years ago
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