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3 years ago

If O is an angle in standard position and its terminal side passes through the point

Mathematics

1 answer:

Nataliya [291]3 years ago

6 0

Answer:

-1/3

Step-by-step explanation:

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1.) A man invested $600 at 8% per annum for 5 years. Calculate: a.) The simple interest payable b.) The total amount of money th

Bezzdna [24]

Answer:

Following are the solution to this question:

Step-by-step explanation:

Using formula:

$\text{Simple Interest} = \frac{P \times R \times T}{100} \\\\\text{ Total amount} = \text{principle}+ \text{Simple Interest}$

In question (1):

$Principle= \$ 600\\Rate = \ 8 \%\\Time= \ 5$

In point a:

$\to \frac{P \times R \times T}{100} \\\\\to \frac{(600 \times 8 \times 5)}{100}\\\\ \to 240$

In point b:

$\to amount = principle \ +\ simple \ interest$

$= 600 + 240 \\\\= 840$

In question (2):

$Principle= \$ 12,450\\Rate = \ 7.25 \%\\Time= \ 6$

In point a:

$\to \frac{P \times R \times T}{100} \\\\\to \frac{(12,450 \times 7.25 \times 6)}{100}\\\\ \to 5,415.75$

In point b:

$\to amount = principle \ +\ simple \ interest$

$= 12,450 + 5,415.75 \\\\= 17,865.75$

The 3 question is incomplete, that's why it can't be solved.

7 0

3 years ago

What is the length of the resulting arrow when you add two arrow in the negative direction?

klio [65]

Bavsgshshhahahahhaa bsbsbsb

7 0

3 years ago

3. For the equation-4y = &r, what is the constant of variation? (1 point)<br> ООО<br> 02

alexandr1967 [171]

Answer:

3).

$- 4y = 8x \\ \frac{y}{x} = \frac{8}{ - 4} \\ \frac{y}{x} = - 2 \\ y = - 2x \\ hence \: constant \: is \: - 2$

4).

$y \alpha x \\ y = kx \\ where \: k \: is \: the \: constant \: of \: proportionality \\ when \: y = 24 \: and \: x = 8 \\ substitute \: in \: y = kx \\ 24 = 8k \\ k = \frac{24}{8} \\ k = 3 \\ value \: of \: constant = 3$

If it was by 10, k = 3 by 10

k = 30

5).

$general \: equation \: of \: line \\ y = mx + c \\ but \: m = \frac{2}{3} \: and \: c = 9 \\ substitute \: for \: m \: and \: c \: in \: y = mx + c \\ y = \frac{2}{3} x + 9 \\ alternatively \\ 3y = 2x + 27$

7 0

3 years ago

Suppose the heights of professional horse jockeys are normally distributed with a mean of 62 in. and a standard deviation of 2 i

ch4aika [34]

Mean = 62 in
SD = 2 in

At 16% = 0.16 and using Z tables,

Z≈ -0.99

x =(-0.99*2) + 62 ≈ 60 in

This represents jockeys who are shorter than 60 in.

6 0

3 years ago

On babylonian tablet ybc 4652, a problem is given that translates to this equation: x x plus startfraction x over 7 endfraction

seraphim [82]

The correct option is (A). The solution of the equation is x=48.125.

Given an equation $x+\frac{x}{7}+\frac{1}{11}\left(x+\frac{x}{7}\right)=60$ .

A statement that uses the equal sign to show that two expressions have the same value is called an equation. The equation is represented as ax+by=c.

Firstly, we will apply the distributive property to the given equation a×(b+c)=ab+ac, we get

$x+\frac{x}{7}+\frac{x}{11}+\frac{x}{77}=60$

Now, we will simplify the right-hand side equation by taking LCM, we get

$\begin{aligned}\frac{77x+11x+7x+x}{77}&=60\\ \frac{96x}{77}&=60\end$

Further, we will multiply both sides with 77, we get

77×(96x/77)=77×60

96x=4620

Then, we will divide both sides with 96, we get

96x/96=4620/96

x=48.125

Hence, the solution of the given equation $x+\frac{x}{7}+\frac{x}{11}+\frac{x}{77}=60$ is x=48.125.

Learn more about solution of equation from here brainly.com/question/1477785

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4 0

2 years ago