Answer: 225m^3
Step-by-step explanation:
Volume = Bh where "B" is the area of the base and "h" is the height
So, area of the base = 1/2(length)(height) = 1/2(5)(9) = 22.5 m^2.
Then multiply by the height.
22.5x10= 225m^3
Answer:
(6 - 8t)(6t - 4t²) / ((6t - 4t²)² + 64)⁰‧⁵
Answer:
Nope.
Step-by-step explanation:
area square: s^2 if one side is 2 cm: are ais 4 cm
rhombus square: (big diagonalxsmall diagonal)/2
what counts on the rombus is not the side, but the diagonals. The diagonals are usually longer than the side of the square, so the area of the rombus is bigger.
First Let we solve the Original system of equations:
equation (1): 
equation (2): 
Multiplying equation (1) by 7, we get
Subtracting,
implies 
Then
Thus the solution of the original equation is
Now Let we form the new equation:
Equation 2 is kept unchanged:
Equation (2):
Equation 1 is replaced with the sum of equation 1 and a multiple of equation 2:
Equation (1): 
Now solve this two equations: 
Multiply (1) by 7 and (2) by 8,
Subtracting,
implies
Then x=2.
so the solution for the new system of equation is x=2, y=1.
This Show that the solution to the system of equations 8x − 5y = 11 and 7x − 8y = 6 is the same as the solution to the given system of equations
<u>Answer</u>:
x = 7, y = 2
<u>Explanation</u>:
equations given:
x + 7y = 21
x + 4y = 15
make "x" the subject:
x + 7y = 21
x = 21 - 7y .........equation 1
x + 4y = 15
x = 15 - 4y .......equation 2
Solving both the equations simultaneously:
15 - 4y = 21 - 7y
-4y + 7y = 21 - 15
3y = 6
y = 6 ÷ 3
y = 2
If y is 2
Then x = 21 -7y;
x = 21 - 7(2)
x = 21 - 14
x = 7
