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EleoNora [17]
3 years ago
8

Help me with this pls

Mathematics
1 answer:
yulyashka [42]3 years ago
7 0

Answer: A. 90° clockwise, E. 270° Counterclockwise

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Evaluate x-2y when x=3,y=-3
adelina 88 [10]

Answer: 9

Step-by-step explanation:

3-2x-3

2x-3=-6

3--6=3+6=9

8 0
3 years ago
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Plzzzz help Lia brought 21 shirts and plants. Her total was $357. Pants cost $25 each, and shirts cost $14.50 each. How many of
OverLord2011 [107]

Answer:

she brought 21 shirts and 2 pants

Step-by-step explanation:

shirts

21× 14.50 = 304.5

357- 304.5 = 52.5

pants

52.5 ÷ 25 = 2.1

5 0
3 years ago
Use the Law of Sines to solve the triangle. (Let b = 47.7 yd. Round your answers for a and c to two decimal places.)
klio [65]

Answer:

C = 68.667°

a = 123.31 yd.

c = 114.90 yd.

Step-by-step explanation:

The missing image for the question is attached to this solution.

In the missing image, a triangle AB is given with angles A and B given to be 88° 35' and 22° 45' respectively

We are them told to find angle C and side a and c given that side b = 47.7 yd.

A = 88° 35' = 88° + (35/60)° = 88.583°

B = 22° 45' = 22° + (45/60)° = 22.75°

The sum of angles in a triangle = 180°

A + B + C = 180°

C = 180° - (A + B) = 180° - (88.583° + 22.75°) = 68.667°

The sine law is given as

(a/sin A) = (b/sin B) = (c/sin C)

Using the first two terms of the sine law

(a/sin A) = (b/sin B)

a = ?

A = 88.583°

b = 47.7 yd.

B = 22.75°

(a/sin 88.583°) = (47.7/sin 22.75°)

a = (47.7 × sin 88.583°) ÷ sin 22.75°

a = 123.31 yd.

Using the last two terms of the sine law

(b/sin B) = (c/sin C)

b = 47.7 yd.

B = 22.75°

c = ?

C = 68.667°

(47.7/sin 22.75°) = (c/sin 68.667°)

c = (47.7 × sin 68.667°) ÷ sin 22.75°

c = 114.90 yd.

Hope this Helps!!!

8 0
3 years ago
4 9/10 divided by 2 3/5
lora16 [44]
<span>4 9/10 divided by 2 3/5

</span>4 9/10 = 49/10
2 3/5 = 13/5 

so
(49/10) / (13/5)
=49/10 * 5/13
= 49/26
or
= 1 23/26
8 0
3 years ago
Which equation represents “nine less than k is three”?
evablogger [386]

Answer:

k - 9 = 3

And k = 12

5 0
3 years ago
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