Answer:>
Step-by-step explanation:
What figure is the question talking about lmk ?
Step-by-step explanation:
TS = 4x - 7
x = -7/4
SV = 5x -15
x = -15/5
= -3
TV = -7/4 + -3
= -3 3/4
= -4.75
(-1,-2) and (-1,4)
so these have same x values, but different y values, so these are on differnt sidef of circle
distanc between them is 6
6/2=3
radius=3
so move 3 units up from (-1,-2)
(-1,1)
so
if center is (h,k) and radius is r then
(x-h)^2+(y-k)^2=r^2
(-1,1) is center and r=3
(x-(-1))^2+(y-1)^2=3^2
(x+1)^2+(y-1)^2=9
Answer:
![f(4)=\frac{1}{2}](https://tex.z-dn.net/?f=f%284%29%3D%5Cfrac%7B1%7D%7B2%7D)
f(x) = 4 when x is 8
Step-by-step explanation:
Domain is the set of x values that make the function defined. Allowed x values for the function (mapping).
The Range is the set of y values that make the function defined. Allowed y values for the function (mapping).
- Whenever we need to find f(a), suppose, then we look for "a" in the domain and see its corresponding value mapping in the range.
- Whenever we will be given a value for f(x) = a, suppose, and we have to find "x", we look at the value a in the range and find corresponding x value in the domain.
Firstly, we need f(4), so we look for "4" in domain and see which number it corresponds to in range.
That is ![\frac{1}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D)
Thus,
![f(4)=\frac{1}{2}](https://tex.z-dn.net/?f=f%284%29%3D%5Cfrac%7B1%7D%7B2%7D)
Next,
We want "x" value that gives us a "y" value of 4. We look for "4" in the range and see which value it corresponds to. That is "8". So,
f(8) = 4