Answer:
a) 47.55
b) 58
c) 47.88
Step-by-step explanation:
Given that the size of the orders is uniformly distributed over the interval
$25 ( a ) to $80 ( b )
<u>a) Determine the value for the first order size generated based on 0.41</u>
parameter for normal distribution is given as ; a = 25, b = 80
size/value of order = a + random number ( b - a )
= 25 + 0.41 ( 80 - 25 )
= 47.55
<u>b) Value of the last order generated based on random number (0.6)</u>
= a + random number ( b - a )
= 25 + 0.6 ( 80 - 25 )
= 25 + 33 = 58
<u>c) Average order size </u>
= ∑ order 1 + order 2 + ----- + order 10 ) / 10
= (47.55 + ...... + 58 ) / 10
= 478.8 / 10 = 47.88
Answer:
Step-by-step explanation:
12 met fans
Answer:
Less than. <
Step-by-step explanation:
I am not sure, but this is what I got:
<span>Pipe ALONE = 18 hours
Pipe ALONE in 1 hour = 1/18 of the pool
Hose ALONE in 1 hour = 1/25 of the pool
TOGETHER in 1 HOUR = 1/18 +1/25 = 43/450
TOGETHER they will fill the pool in 450/43 hours
So 5/6 of the pool will take 5/6 X 450/43 = 2250/ 258 = 8.7209302 hours OR
8 hours AND 43.26 minutes ANSWER
</span>
Hope this helps!
Add 37 + 9 = 46
If thats not your answer theres more.
46 divided by 5 = 9.2
