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3 years ago

Complete to solve 56+4 56+4 =(50+__)+4 =50+( +4) =50 +_ =____

Mathematics

2 answers:

kakasveta [241]3 years ago

8 0

Answer:

Step-by-step explanation:

Add 6 to 50: 50+6=56. When you add 6 to 50 you get 56. After that add 4

(50+___)+4 the blank is 6

so: (50+6)+4

50+(___+4) the blank is 6

so: 50+(6+4)

50+___ the blank is 10

=60

Lunna [17]3 years ago

6 0

Answer:

Step-by-step explanation:

=(50+6)+4

=50+(6+4)

=50+10

=60

So therefore your answer must be 60

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gavmur [86]

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$9x^2 - 18 x = - 99$

Divide by 9 through
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Add (b/2)^2 to form perfect square
$x^2 - 2 x + ( \frac{2}{2} )^2 = - 11 + ( \frac{2}{2} )^2$

Form perfect square
$(x - 1)^2 = - 10$

Square root both sides to find x
$x - 1 = \pm \sqrt{-10}$

add 1 on both sides
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3 years ago

You have saved $1350 and are now going to invest it. The account you have chosen will compound continuously and after 10 years y

Roman55 [17]

Answer:

The account interest rate is 0.80%

Step-by-step explanation:

A=P(1+r/100)^10

1462=1350(1+r/100)^10{divide both sides by 1350}

1462/1350=(1+r/100)^10{find the 10th root of both sides}

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3 years ago

Given the following function, find h(-3). h(x) = 7x2-4

LuckyWell [14K]

Answer:

h=-59/3

Explanation-

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4 years ago

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Shtirlitz [24]

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3 years ago

Quarters are currently minted with weights normally distributed and having a standard deviation of 0.065. New equipment is being

Ilya [14]

Answer:

Yes, the new equipment appear to be effective in reducing the variation of weights.

Step-by-step explanation:

We are given that Quarters are currently minted with weights normally distributed and having a standard deviation of 0.065.

A simple random sample of 25 quarters is obtained from those manufactured with the new equipment, and this sample has a standard deviation of 0.047.

Let $\sigma$ = standard deviation of weights of new equipment.

SO, Null Hypothesis, $H_0$ : $\sigma \geq$ 0.065 {means that the new equipment have weights with a standard deviation more than or equal to 0.065}

Alternate Hypothesis, $H_A$ : $\sigma$ < 0.065 {means that the new equipment have weights with a standard deviation less than 0.065}

The test statistics that would be used here One-sample chi-square test statistics;

T.S. = $\frac{(n-1)s^{2} }{\sigma^{2} }$ ~ $\chi^{2}__n_-_1$

where, s = sample standard deviation = 0.047

n = sample of quarters = 25

So, the test statistics = $\frac{(25-1)\times 0.047^{2} }{0.065^{2} }$ ~ $\chi^{2}__2_4$

= 12.55

The value of chi-square test statistics is 12.55.

Now, at 0.05 significance level the chi-square table gives critical value of 13.85 at 24 degree of freedom for left-tailed test.

Since our test statistic is less than the critical value of chi-square as 12.55 < 13.85, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that the new equipment have weights with a standard deviation less than 0.065.

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3 years ago

Complete to solve 56+4 56+4 =(50+____)+4 =50+(____ +4) =50 +___ =____

Complete to solve 56+4 56+4 =(50+__)+4 =50+( +4) =50 +_ =____