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SOVA2 [1]
3 years ago
15

BRAINLIEST FOR THE RIGHT ANSWER..... EMERGENCY

Mathematics
2 answers:
xenn [34]3 years ago
6 0

Answer:

$15.45 i believe

Step-by-step explanation:

3% of 15 is 0.45. add 0.45 + 15 = 15.45

White raven [17]3 years ago
6 0

Answer:

$12:00

Step-by-step explanation:

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The perimeter is? Somebody help please !!!!!!!
Alexus [3.1K]

Answer:

The perimeter is 52

Step-by-step explanation:

Just add all the numbers together

13 + 9 + 3 + 7 + 5 + 15 = 22 + 10 + 20 = 32 + 20 = 52

4 0
3 years ago
Whats the answer of -5+-2p=-9
Nikolay [14]

Answer:

p = 2

Step-by-step explanation:

Step 1: Write equation

-5 + -2p = -9

Step 2: Solve for <em>p</em>

<u>Simplify:</u> -5 - 2p = -9

<u>Add 5 to both sides:</u> -2p = -4

<u>Divide both sides by -2:</u> p = 2

Step 3: Check

<em>Plug in p to verify it's a solution.</em>

-5 - 2(2) = -9

-5 - 4 = -9

-9 = -9

7 0
3 years ago
Read 2 more answers
Help question is in picture will mark brainliest
salantis [7]

Answer:

cumblaster.org

Step-by-step explanation:

8 0
2 years ago
A binomial probability experiment is conducted with the given parameters. Compute the probability of x successes in the n indepe
Mila [183]
<h3>Answer:  0.1319</h3>

==========================================

Work Shown:

P(x) = (_n C_x)*(p)^x*(1-p)^{n-x}\\\\P(14) = (_{15} C_{14})*(0.8)^{14}*(1-0.8)^{15-14}\\\\P(14) = 15*(0.8)^{14}*(0.2)^{1}\\\\P(14) \approx 0.13194139533312 \\\\P(14) \approx \boldsymbol{0.1319} \\\\

Side note: you can use the nCr formula to compute _{15} C_{14}; however, it's much quicker to use the shortcut formula _{n} C_{n-1} = n. You can also use Pascal's Triangle to find the value of _{15} C_{14}

3 0
2 years ago
Solve for x: one over eight (8x + 15) = 24
Vsevolod [243]
The answer is 177/8 or one hundred seventy seven over eigth.

1/8(8x + 15) = 24

Multiply both sides by 8:
8* 1/8(8x + 15) = 8 * 24
8x + 15 = 192


Subtract 15 from both sides:
8x +15 - 15 = 192 - 15
8x = 177

Divide both sides by 8:
8x/8 = 177/8
x = 177/8

8 0
3 years ago
Read 2 more answers
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