Given:
The height h of an object after t seconds is

The height of a neighboring 50-foot tall building is modeled by the equation h=50.
The time (t) when the object will be at the same height as the building is found to be t = –2 and t = 5.
To find:
The statement which describes the validity of these solutions.
Solution:
We have,

Here, t is the time in seconds.
For t=-2,



For t=5,



So, the value of h is 50 at t=-2 and t=5.
We know that time is always positive so it cannot be negative value. It means t=-2 is not possible.
The solution t = 5 is the only valid solution to this system since time cannot be negative.
Therefore, the correct option is C.
Nothing on your list <em><u>IS</u></em> a way to write 25 percent.
Answer:
10
Step-by-step explanation:
10/4 = 2.5(fraction)
12/4 = 3
8/4 = 2
24/4 = 6
Answer: t= 460.52 minutes
Step-by-step explanation:Q'=Q/100
Q'= rate in and out of water
Finding the differential equation
Let Q'(t)= The quantity of dye in the tank for t time
But rate in=0 Q/200 ×2=Q'
Q'/Q=-1/100
Dividing by Q gives
Ln/Q/ + c = -1/100 + c1
Integrating both sides gives
Ln/Q/ = -(1/100)t + c2
But c+c1=C2= A constant
Q=C2e(-t/100)
200e-(t/100)
t= ln200
t=460.52minutes
I did my calculations and i rechecked it by redoing the question and I got "37800".