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TEA [102]
2 years ago
6

1/3(z+4)-6=2/3(5-z) ​

Mathematics
1 answer:
chubhunter [2.5K]2 years ago
7 0

Answer:

hope my answer is helpful to you

plz mark me as brainlist and also follow me

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If one leg of a 45-45-90 triangle is 12 cm, find the length of the hypotenuse.
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It’s the third one C)

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Y = 4x - 2<br> y = x + 3
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y=3x+1

Step-by-step explanation:

if im correct you are working on elimination, so you pretty much sub. so the difference between -2 and 3 is positive 1; the difference between 4x and x is 3x

are you working on elimination?

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95% is the answer to your question
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Round to nearest thousandth<br>0.227​
Nutka1998 [239]

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Step-by-step explanation:

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3 years ago
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Use Lagrange multipliers to find the maximum and minimum values of f(x,y)=x+4y subject to the constraint x2+y2=9, if such values
Vesnalui [34]

The Lagrangian is

L(x,y,\lambda)=x+4y+\lambda(x^2+y^2-9)

with critical points where the partial derivatives vanish.

L_x=1+2\lambda x=0\implies x=-\dfrac1{2\lambda}

L_y=4+2\lambda y=0\implies y=-\dfrac2\lambda

L_\lambda=x^2+y^2-9=0

Substitute x,y into the last equation and solve for \lambda:

\left(-\dfrac1{2\lambda}\right)^2+\left(-\dfrac2\lambda\right)^2=9\implies\lambda=\pm\dfrac{\sqrt{17}}6

Then we get two critical points,

(x,y)=\left(-\dfrac3{\sqrt{17}},-\dfrac{12}{\sqrt{17}}\right)\text{ and }(x,y)=\left(\dfrac3{\sqrt{17}},\dfrac{12}{\sqrt{17}}\right)

We get an absolute maximum of 3\sqrt{17}\approx12.369 at the second point, and an absolute minimum of -3\sqrt{17}\approx-12.369 at the first point.

4 0
2 years ago
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