2 years ago

1/3(z+4)-6=2/3(5-z)

Mathematics

1 answer:

chubhunter [2.5K]2 years ago

7 0

Answer:

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Simplify the sum.<br> (4u3 + 4u2 + 2) + (6u3 – 2u + 8)

Elan Coil [88]

Answer:

$10u^{3}+4u^{2}-2u+10$ or $2(5u^{3}+2u^{2}-u+5)$

Step-by-step explanation:

we have

$(4u^{3}+4u^{2} +2)+(6u^{3}-2u+8)$

step 1

Group terms that contain the same variable

$(4u^{3}+6u^{3})+(4u^{2})+(-2u)+(2+8)$

step 2

Combine like terms

$(10u^{3})+(4u^{2})+(-2u)+(10)$

step 3

Eliminate parenthesis

$10u^{3}+4u^{2}-2u+10$

step 4

Factor the number $2$

$2(5u^{3}+2u^{2}-u+5)$

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3 years ago

Read 2 more answers

The width of a rectangle is 7 meters greater than its length. If the area of the rectangle is 170 square meters, write the quadr

soldier1979 [14.2K]

Since x is the length, then x+7 has to be the width.
The area of a rectangle can be found via the formula :
A = length * width
So if we replace the area with the given number (170) and the length, and width, with what we assumed, we get..
170 = x * (x+7)
[which is.. ]
170 = x^2 +7x
0 = x^2 +7x - 170

And that is the answer.

4 0

3 years ago

1/3(z+4)-6=2/3(5-z) ​

1/3(z+4)-6=2/3(5-z)