Answer:

Step-by-step explanation:
The picture of the question in the attached figure
step 1
Let
r ---> the radius of the sector
s ---> the arc length of sector
Find the radius r
we know that



solve for r

step 2
Find the value of s

substitute the value of r

step 3
we know that
The area of complete circle is equal to

The complete circle subtends a central angle of 2π radians
so
using proportion find the area of the sector by a central angle of angle theta
Let
A ---> the area of sector with central angle theta

substitute the value of r


Convert to function notation

The answer I believe is c
Answer:3x-x+2=4
Step-by-step explanation: source: (Too much work) srry
1. C
2. A
3. B
Hope This Helped!
<u><em>(Brainliest will be appreciated)</em></u>
Step-by-step explanation:
1) 



2) 



3) 




4) 





5) 



