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3 years ago

5

You are working with an athlete who has a 1RM in the Back! Squat of 200 kg. What is the maximum number of repetitions they could

do with 150 kg? a. 10b. 8c. 6d. 4e. 2

1 answer:

pickupchik [31]3 years ago

7 0

Answer:

The answer is "Option a"

Step-by-step explanation:

In this question, the answer is "option a", which is equal to 10, and which is based on the training load base chart.

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What are benchmarks when using rounding?

cricket20 [7]

Answer:

Benchmark can be defined as the standard or reference point against which something can be measured, compared, or assessed.

Step-by-step explanation:

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3 years ago

A metal cylinder can with an open top and closed bottom is to have volume 4 cubic feet. Approximate the dimensions that require

Aleksandr-060686 [28]

Answer:

$r\approx 1.084\ feet$

$h\approx 1.084\ feet$

$\displaystyle A=11.07\ ft^2$

Step-by-step explanation:

<u>Optimizing With Derivatives </u>

The procedure to optimize a function (find its maximum or minimum) consists in :

Produce a function which depends on only one variable
Compute the first derivative and set it equal to 0
Find the values for the variable, called critical points
Compute the second derivative
Evaluate the second derivative in the critical points. If it results positive, the critical point is a minimum, if it's negative, the critical point is a maximum

We know a cylinder has a volume of 4 $ft^3$ . The volume of a cylinder is given by

$\displaystyle V=\pi r^2h$

Equating it to 4

$\displaystyle \pi r^2h=4$

Let's solve for h

$\displaystyle h=\frac{4}{\pi r^2}$

A cylinder with an open-top has only one circle as the shape of the lid and has a lateral area computed as a rectangle of height h and base equal to the length of a circle. Thus, the total area of the material to make the cylinder is

$\displaystyle A=\pi r^2+2\pi rh$

Replacing the formula of h

$\displaystyle A=\pi r^2+2\pi r \left (\frac{4}{\pi r^2}\right )$

Simplifying

$\displaystyle A=\pi r^2+\frac{8}{r}$

We have the function of the area in terms of one variable. Now we compute the first derivative and equal it to zero

$\displaystyle A'=2\pi r-\frac{8}{r^2}=0$

Rearranging

$\displaystyle 2\pi r=\frac{8}{r^2}$

Solving for r

$\displaystyle r^3=\frac{4}{\pi }$

$\displaystyle r=\sqrt[3]{\frac{4}{\pi }}\approx 1.084\ feet$

Computing h

$\displaystyle h=\frac{4}{\pi \ r^2}\approx 1.084\ feet$

We can see the height and the radius are of the same size. We check if the critical point is a maximum or a minimum by computing the second derivative

$\displaystyle A''=2\pi+\frac{16}{r^3}$

We can see it will be always positive regardless of the value of r (assumed positive too), so the critical point is a minimum.

The minimum area is

$\displaystyle A=\pi(1.084)^2+\frac{8}{1.084}$

$\boxed{ A=11.07\ ft^2}$

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2 years ago

85) A6-foot man casts an 8-foot shadow. How tall is a tree that casts a<br> 20-foot shadow?

vichka [17]

Answer:

15 foot

Step-by-step explanation:

6 foot = 8 foot shadow

3 foot= 4 foot shadow

15 foot=20 foot shadow

please give me brainliest!!!

5 0

3 years ago

Solve the variable in the following proportion. 3.6/y=1.2/2

Molodets [167]

Hello :
<span>3.6/y=1.2/2
1.2 y = 2(3.6)
y = 2(3.6)/1.2
y=6</span>

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3 years ago

A shopper buys cat food in bags of 3 lbs. Her cat eats 34 lb each week. How many weeks does one bag last?

Vika [28.1K]

11 weeks hope this helps

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2 years ago