The point (-1,2) is in quadrant 2
The answer should be -1/2.
Based on the one-sample t-test that Mark is using, the two true statements are:
- c.)The value for the degrees of freedom for Mark's sample population is five.
- d.)The t-distribution that Mark uses has thicker tails than a standard normal distribution.
<h3>What are the degrees of freedom?</h3><h3 />
The number of subjects in the data given by Mark is 6 subjects.
The degrees of freedom can be found as:
= n - 1
= 6 - 1
= 5
This is a low degrees of freedom and one characteristic of low degrees of freedom is that their tails are shorter and thicker when compared to standard normal distributions.
Options for this question are:
- a.)The t-distribution that Mark uses has thinner tails than a standard distribution.
- b.)Mark would use the population standard deviation to calculate a t-distribution.
- c.)The value for the degrees of freedom for Mark's sample population is five.
- d.)The t-distribution that Mark uses has thicker tails than a standard normal distribution.
- e.)The value for the degrees of freedom for Mark's sample population is six.
Find out more on the degrees of freedom at brainly.com/question/17305237
#SPJ1
Answer:
10y + 12x +38
Step-by-step explanation:
Take the common variable aside
4y + 6y + 8x + 4x + 6 + 25 + 7
10y + 12x + 38
Answer:
C. C only
Step-by-step explanation:
Well to determine if the given graphs are functions we need to do the vertical line test to all the graphs,
A. This fails the vertical line test because the vertical line could pass through 2 points on the lines.
B. this also fails because a vertical line could pass through 2 points.
C. This passes because the vertical line doesn’t touch 2 points.
