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Zigmanuir [339]
3 years ago
9

A store runs a promotion in which every 500th customer (500th, 1000th, 1500th, ...) received a free gift, every 800th (800th, 16

00th, ...) customer receives a voucher, and every 1200th (1200th, 2400th, ...) customer receives a discount. Which lucky customer will be the first to receive all three promotional prizes?
Mathematics
1 answer:
postnew [5]3 years ago
3 0

The answer is 12,000

To solve this question, you have to find the least common multiple of the three promotional prizes. The factor of 500, 800 and 1200 would be:

500= 2*2*5*5*5= 2^2 * 5^3

800= 2*2*2*2*2*5*5= 2^5 * 5^2

1200= 2*2*2*2*3*5*5= 2^4 * 3 *5^2

The LCM of those three number would be: 2^5 * 3 * 5^3= 12,000

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Topic 13 Online Assessment
telo118 [61]

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Tomas is incorrect.

Step-by-step explanation:

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there are eight competitors in each ring for a raw kwon do to tournament if there are 96 competitors in the tournament how many
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