3/2 because you divide both by 2
The given conclusion that ABCD is a square is not valid.
Given that, AC⊥BD and AC≅BD.
We need to determine if the given conclusion is valid.
<h3>What are the properties of squares?</h3>
A square is a closed figure with four equal sides and the interior angles of a square are equal to 90°. A square can have a wide range of properties. Some of the important properties of a square are given below.
- A square is a quadrilateral with 4 sides and 4 vertices.
- All four sides of the square are equal to each other.
- The opposite sides of a square are parallel to each other.
- The interior angle of a square at each vertex is 90°.
- The diagonals of a square bisect each other at 90°.
- The length of the diagonals is equal.
Given that, the diagonals of a quadrilateral are perpendicular to each other and the diagonals of a quadrilateral are equal.
Now, from the properties of a square, we understood that the diagonals of a square are perpendicular to each other and the diagonals of a square are equal.
So, the given quadrilateral can be a square. But only with these two properties can not conclude the quadrilateral is a square.
Therefore, the given conclusion that ABCD is a square is not valid.
To learn more about the properties of a square visit:
brainly.com/question/20377250.
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Answer:
94.2 in squared
Step-by-step explanation:
lateral area plus area of both flat sides
37.68 + 2(3.14*3^2)
37.68 + 56.52 = 94.2 in squared
To solve for the last side of the triangle, use the Pythagorean Theorem:
(8)^2 + x^2 = (9)^2
x = sqrt of 17
However, this is a NEGATIVE sqrt 17 because the terminal side is in quadrant 4, meaning that this side is under the X-axis and therefore negative.
Now that you know the side opposite of u in the triangle, do opposite/hypotenuse.
sin u = -(sqrt 17)/9
