What is the shape of the following distribution? {9, 10, 10, 11, 11, 12, 12, 13, 13, 13, 14, 14, 14, 14, 15, 15, 15, 15, 16, 16,
babunello [35]
The shape of the distribution with the following data set you gave is skewed to the left or negatively skewed. This is because the frequency of each number increases as its value increases.
Answer:
150 feet by 300 feet.
Step-by-step explanation:
The fence is to enclose a rectangular area of 45,000 ft squared.
If the dimensions of the rectangle are x and y
Area of a rectangle = xy
- xy=45000

Perimeter of the Rectangle =2x+2y
Fencing material costs $ 3 per foot for the two sides facing north and south and $6 per foot for the other two sides.
- Cost of Fencing, C=$(6*2x+3*2y)=$(12x+6y)
Substitute
into the Cost to get C(y)
C=12x+6y

The value at which the cost is least expensive is at the minimum point of C(y), when the derivative is zero.


Recall,

Since x=150, y=300
The dimensions that will be least expensive to build is 150 feet by 300 feet.
For this case we have:
Let a function of the form 
By definition, to graph
, where
, we must move the graph of f (x), h units to the left.
We observe that the red graph has the same form as the black graph, but it is displaced "h" units to the left.
It is observed that 
So, if the black graph is given by
, the red graph is given by: 
Answer:

Option A
Answer:
Option D. (x + 4)(x + 1)
Step-by-step explanation:
From the question given above, the following data were obtained:
C = (6x + 2) L
D = (3x² + 6x + 9) L
Also, we were told that half of container C is full and one third of container D is full. Thus the volume of liquid in each container can be obtained as follow:
Volume in C = ½C
Volume in C = ½(6x + 2)
Volume in C = (3x + 1) L
Volume in D = ⅓D
Volume in D = ⅓(3x² + 6x + 9)
Volume in D = (x² + 2x + 3) L
Finally, we shall determine the total volume of liquid in the two containers. This can be obtained as follow:
Volume in C = (3x + 1) L
Volume in D = (x² + 2x + 3) L
Total volume =?
Total volume = Volume in C + Volume in D
Total volume = (3x + 1) + (x² + 2x + 3)
= 3x + 1 + x² + 2x + 3
= x² + 5x + 4
Factorise
x² + 5x + 4
x² + x + 4x + 4
x(x + 1) + 4(x + 1)
(x + 4)(x + 1)
Thus, the total volume of liquid in the two containers is (x + 4)(x + 1) L.