The discontinuity occurs at x = 0, since that is the only "problem" place in the graph that makes the function undefined. A vertical asymptote exists there. It is nonremoveable.
Answer:
Answer:
g(x)=-6/5x+1/2
h(x)=-6/5x-1/2
Step-by-step explanation:
1). g(x)=−f(x) ?
f(x)=6/5x−1/2
g(x)=−(6/5x−1/2)
g(x)=-6/5x+1/2
2). h(x)=f(−x) ?
f(-x)=6/5(-x)−1/2
f(-x)=-6/5x-1/2
h(x)=-6/5x-1/2
Step-by-step explanation:
Answer:
Slope is 5
Step-by-step explanation:
(1, 2) and (3, 12)
m= (y2-y1)/(x2-x1)
m= (12-2)/(3-1)
m= 10/2
m= 5
