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shepuryov [24]
3 years ago
7

7.216 and 7.203 compare the two numbers

Mathematics
2 answers:
svet-max [94.6K]3 years ago
7 0

Answer:

Step-by-step explanation:

3. write >,<, or =for the two numbers.

7.216____7.203. select one:<. >.

ser-zykov [4K]3 years ago
5 0

Answer:

7.216 > 7.203

Step-by-step explanation:

This is the answer because:

1) First, let's look at the ones place. In both numbers, there is a 7 as a ones place

2) Next, let's look at the tenths place. In both numbers, there is a 2 as the tenths place

3) Then, let's look at the hundredth place. In 7.216 there is a 1 in the hundredths place. In the other number, 7.203, there is a 0 in the hundredths place. We now know that 7.216 is greater than 7.203

Hope this helps!

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slamgirl [31]

Answer:

P=14

Step-by-step explanation:

Since P depends on two variables x and y as the sum of the two, then;

P = 3+ 11

P = 14

3 0
3 years ago
For #1-8, solve the equation for the indicated variable:<br> Solve for x:<br> 1.<br><br> 3x + 2 = 8
Karo-lina-s [1.5K]

Steps to solve:

3x + 2 = 8

~Subtract 2 to both sides

3x = 6

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Best of Luck!

5 0
3 years ago
Which of the following graphs represent a nonproportional relationship? Select all that apply.
natka813 [3]

Answer:

2nd, 4th and 5th one

Step-by-step explanation:

Hey There!

So remember in order for it to be a proportional relationship it has to be a straight line and it has to go through the origin (0,0)

The 2nd, 4th and 5th ones are non proportional relationships

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3 0
3 years ago
Read 2 more answers
A) How many ways can 2 integers from 1,2,...,100 be selected
Anna007 [38]

Answer with explanation:

→Number of Integers from 1 to 100

                                            =100(50 Odd +50 Even)

→50 Even =2,4,6,8,10,12,14,16,...............................100

→50 Odd=1,3,,5,7,9,..................................99.

→Sum of Two even integers is even.

→Sum of two odd Integers is odd.

→Sum of an Odd and even Integer is Odd.

(a)

Number of ways of Selecting 2 integers from 50 Integers ,so that their sum is even,

   =Selecting 2 Even integers from 50 Even Integers , and Selecting 2 Odd integers from 50 Odd integers ,as Order of arrangement is not Important, ,

        =_{2}^{50}\textrm{C}+_{2}^{50}\textrm{C}\\\\=\frac{50!}{(50-2)!(2!)}+\frac{50!}{(50-2)!(2!)}\\\\=\frac{50!}{48!\times 2!}+\frac{50!}{48!\times 2!}\\\\=\frac{50 \times 49}{2}+\frac{50 \times 49}{2}\\\\=1225+1225\\\\=2450

=4900 ways

(b)

Number of ways of Selecting 2 integers from 100 Integers ,so that their sum is Odd,

   =Selecting 1 even integer from 50 Integers, and 1 Odd integer from 50 Odd integers, as Order of arrangement is not Important,

        =_{1}^{50}\textrm{C}\times _{1}^{50}\textrm{C}\\\\=\frac{50!}{(50-1)!(1!)} \times \frac{50!}{(50-1)!(1!)}\\\\=\frac{50!}{49!\times 1!}\times \frac{50!}{49!\times 1!}\\\\=50\times 50\\\\=2500

=2500 ways

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3 years ago
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