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belka [17]
2 years ago
6

Find the angle of x (view picture)

Mathematics
2 answers:
Alex17521 [72]2 years ago
3 0

Answer:

i dont understand this qustion\

Step-by-step explanation:

Dvinal [7]2 years ago
3 0

Answer:

60

The 2 angles in the triangle add up to 120, there are 180 degrees so the last one is 60. 60 is equal to x because of co-interior angles

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A population of rabbits in a lab, p(x), can be modeled by the function p(x) = 20(1.014)x , where x represents the number of days
Nitella [24]

Answer:

20 = initial population of the rabbits

1.014 = growth rate of the rabbits

the average rate of change from day 50 to day 100 is 0.8

Step-by-step explanation:

A population of rabbits in a lab, p(x), can be modeled by the function

p(x) = 20(1.014)^x

This model is exponential. Where 20 = initial population of the rabbits

1.014 = growth rate of the rabbits with 1.4% increase rate of the rabbits

To find the average rate of change from day 50 to day 100,

find the population p(50) and p(100). Subtract them and divide by 100 - 50 = 50. 

p(50) = 20(1.014)50 = 40.08... 

p(100) = 20(1.014)100 = 80.32... 

(80.32 - 40.08) / (100 - 50) = 40.24/50 = 0.8048. which is approximately 0.8 to the nearest tenth. 

The rate of change is 0.8. 

7 0
3 years ago
The coordinates of point T are (0,6). The midpoint of ST is (3, -4). Find the coordinates of point S
bezimeni [28]

Answer:

S = (-8, 0 )

Step-by-step explanation:

7 0
3 years ago
Two pounds of bananas cost $1.16 what would be the cost of 5pounds s of bananas
ivann1987 [24]
If 2 lb of bananas cost $1.16, then each pound costs $0.58.

0.58 * 5 = 2.9

So 5 lb of bananas will cost $2.90.

Hope this helps!
6 0
3 years ago
Read 2 more answers
The rate of transmission in a telegraph cable is observed to be proportional to x2ln(1/x) where x is the ratio of the radius of
sergij07 [2.7K]

Answer:

The value of x that gives the maximum transmission is 1/√e ≅0.607

Step-by-step explanation:

Lets call f the rate function f. Note that f(x) = k * x^2ln(1/x), where k is a positive constant (this is because f is proportional to the other expression). In order to compute the maximum of f in (0,1), we derivate f, using the product rule.

f'(x) = k*((x^2)'*ln(1/x) + x^2*(ln(1/x)')) = k*(2x\,ln(1/x)+x^2*(\frac{1}{1/x}*(-\frac{1}{x^2})))\\= k * (2x \, ln(1/x)-x)

We need to equalize f' to 0

  • k*(2x ln(1/x) - x) = 0 -------- We send k dividing to the other side
  • 2x ln(1/x) - x = 0 -------- Now we take the x and move it to the other side
  • 2x ln(1/x) = x -- Now, we send 2x dividing (note that x>0, so we can divide)
  • ln(1/x) = x/2x = 1/2 -------  we send the natural logarithm as exp
  • 1/x = e^(1/2)
  • x = 1/e^(1/2) = 1/√e ≅ 0.607

Thus, the value of x that gives the maximum transmission is 1/√e.

7 0
3 years ago
Context inequality systems on
MariettaO [177]
Yea I don’t know it’s b
8 0
2 years ago
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