Hey there! :D
If there are 3 times as many boys than girls:
3+1=4
116/4= 29
29*3= 87
29*1= 29
There are 87 boys and 29 girls.
I hope this helps!
~kaikers
The amount in the passbook account is $11,000 and the money in the money market account is $8000
Let:
a represent the unknown amount in the passbook account
b represent the unknown amount in the money market account
From the question, the following information can be gathered:
- The money in the passbook account exceeds the amount in the money market account.
This information can be represented with this equation : a - b = 3000
- The interest paid on the passbook account exceeds the interest paid on the money market account.
This information can be represented with this equation : 0.08a - 0.10b = 80
The two equations gotten above would be solved using simultaneous equation and the elimination method
a - b = 3000 equation 1
0.08a - 0.10b = 80 equation 2
Multiply equation 1 by 0.08
0.08 - 0.08b = 240 equation 3
Subtract equation 2 from 3
0.02b = 160
Divide both sides of the equation by 0.02
b = 8000
Substitute for b in equation 1
a - 8000 = 3000
Add 8000 to both sides
a = 11,000
To learn more about simultaneous equations, please check: brainly.com/question/23589883?referrer=searchResults
Answer:
Exponent laws:
1. Product law

In product law if bases are same then we add their respective powers.But if bases are different we can't add their powers.
x=base, a,b,c=exponent
If x=2 and a=3, b=5 , and c=10, then

2.Product raised to a power
1. ![[x^{a}]^{c}=x^{ac}](https://tex.z-dn.net/?f=%5Bx%5E%7Ba%7D%5D%5E%7Bc%7D%3Dx%5E%7Bac%7D)
2. ![[x^{a}\times x^{b}]^{c}=[x^{a+b}]^{c}=x^{ac+bc}](https://tex.z-dn.net/?f=%5Bx%5E%7Ba%7D%5Ctimes%20x%5E%7Bb%7D%5D%5E%7Bc%7D%3D%5Bx%5E%7Ba%2Bb%7D%5D%5E%7Bc%7D%3Dx%5E%7Bac%2Bbc%7D)
If product is raised to a certain power , keeping the base same , we just multiply the powers.for example
and
![[2^{3}\times3^{2}]^{2}=[2^{3}]^2 \times[3^{2}]^{2}=2^{6}\times3^{4}](https://tex.z-dn.net/?f=%5B2%5E%7B3%7D%5Ctimes3%5E%7B2%7D%5D%5E%7B2%7D%3D%5B2%5E%7B3%7D%5D%5E2%20%5Ctimes%5B3%5E%7B2%7D%5D%5E%7B2%7D%3D2%5E%7B6%7D%5Ctimes3%5E%7B4%7D)
![[2^{3}\times2^{2}]^{2}=[2^{3+2}]^{2}=[2^{5}]^{2}=2^{10}](https://tex.z-dn.net/?f=%5B2%5E%7B3%7D%5Ctimes2%5E%7B2%7D%5D%5E%7B2%7D%3D%5B2%5E%7B3%2B2%7D%5D%5E%7B2%7D%3D%5B2%5E%7B5%7D%5D%5E%7B2%7D%3D2%5E%7B10%7D)
Answer:
<h2>A . 6</h2>
Step-by-step explanation:

Answer:
9.22 repeating, also I'm doing fine :) wear a mask when you go anywhere around people (remember 6 ft), wash your hands, and stay safe!!!
Step-by-step explanation:
First I turned the fraction given into a mixed fraction, so 83/9, I just did that by multiplying 9 by 9 and then add 2.
When converted to a decimal you get 9.22 repeating