A converging lens of focal length 5 cm is placed at a distance of 20
1 answer:
The object should be placed 20/cm from the lens so as to form its real image on the screen
<h3>Mirror equation</h3>
The mirror equation is given according to the expression below;
1/f = 1/u + 1/v
where
f is the focal length
u is the object distance
v is the image distance
Given the following parameters
f = 5cm
v = 20cm
Required
object distance u
Substitute
1/5 = 1/u +1/20
1/u = 1/5-1/20
1/u = 3/20
u = 20/3 cm
Hence the object should be placed 20/cm from the lens so as to form its real image on the screen
Learn more on mirror equation here; brainly.com/question/27924393
#SPJ1
You might be interested in
Answer:
Which equation do I refer to?
Step-by-step explanation:
Answer:
2x - 10
Step-by-step explanation:
2(x - 5)
distribute
2*x - 2*5
2x - 2*5
2x - 10
First you should combine n/6-5n/12
that goes to 2n/12-5n/12 which equals -3n/12
then you should cross multiply -3n/12 by 1/16
12(1)=-3n(16)
12=-48n then solve for n by dividing by -48
-12/48=n simplify -1/4=n or -.25=n
The answer would be because
I'm guessing to probably divide $45,000 by 23 and then multiply that answer by $12,000. I hope this helps
