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maks197457 [2]
2 years ago
13

A converging lens of focal length 5 cm is placed at a distance of 20

Mathematics
1 answer:
lesya [120]2 years ago
4 0

The object should be placed 20/cm from the lens so as to form its real image on the screen

<h3>Mirror equation</h3>

The mirror equation is given according to the expression below;

1/f = 1/u + 1/v

where

f is the focal length

u is the object distance

v is the image distance

Given the following parameters

f = 5cm

v = 20cm

Required

object distance u

Substitute

1/5 = 1/u +1/20

1/u = 1/5-1/20
1/u = 3/20

u = 20/3 cm

Hence the object should be placed 20/cm from the lens so as to form its real image on the screen

Learn more on mirror equation here; brainly.com/question/27924393

#SPJ1

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a spiner has 5 equal sized sections with different colors. you spin the spinner 50 times what is th theoretical and experimental
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3 years ago
52 998 x 67 = (1,000 - 998) x 67
Tresset [83]

Given:

\to \bold{52,998 \times 67 = (1,000 - 998)  \times 67}

To find:

Proving

Solution:

\to \bold{52,998 \times 67 = (1,000 - 998)  \times 67}

Solving L.H.S part:

\to \bold{52,998 \times 67}\\\\\to \bold{3,550,866}\\\\

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Therefore \bold{L.H.S \bold{\neq} R.H.S}

Learn more:

brainly.com/question/24706365

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Answer:

Step-by-step explanation:

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Look at the attached image as example.

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