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3 years ago

Which table has a constant of proportionality between y and x of 1/4?

Mathematics

1 answer:

worty [1.4K]3 years ago

4 0

In order to find constant of proportionality, you have to use the equation, x(?)=y
The ? being the number to plug in, which would be 1/4 in this case. 8 times 1/4 is equal to 2 and so on.

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Using the table, what is the relative frequency of the blue beads?

Pepsi [2]

20% is ur answer to the question

7 0

3 years ago

Which expression is equivalent to 28 + 7? Prove your answer by showing your work.

OverLord2011 [107]

Answer:

ok so first lets find the answer to the original question

28+7=35

so lets find which one is equal to 35

7(4+1)=28+7=35 yes

4(7+1)=28+4=32 no

4(7+3)=28+12=40 no

7(4+7)=28+49=77 no

a is the answer

Hope This Helps!!!

6 0

2 years ago

Let X be a Bernoulli rv with pmf as in Example 3.18. a. Compute E(X2 ). b. Show that V(X) 5 p(1 2 p). c. Compute E(X79).

spayn [35]

The Bernoulli distribution is a distribution whose random variable can only take 0 or 1

The value of E(x2) is p
The value of V(x) is p(1 - p)
The value of E(x79) is p

<h3>How to compute E(x2)</h3>

The distribution is given as:

p(0) = 1 - p

p(1) = p

The expected value of x2, E(x2) is calculated as:

$E(x^2) = \sum x^2 * P(x)$

So, we have:

$E(x^2) = 0^2 * (1- p) + 1^2 * p$

Evaluate the exponents

$E(x^2) = 0 * (1- p) + 1 * p$

Multiply

$E(x^2) = 0 +p$

Add

$E(x^2) = p$

Hence, the value of E(x2) is p

<h3>How to compute V(x)</h3>

This is calculated as:

$V(x) = E(x^2) - (E(x))^2$

Start by calculating E(x) using:

$E(x) = \sum x * P(x)$

So, we have:

$E(x) = 0 * (1- p) + 1 * p$

$E(x) = p$

Recall that:

$V(x) = E(x^2) - (E(x))^2$

So, we have:

$V(x) = p - p^2$

Factor out p

$V(x) = p(1 - p)$

Hence, the value of V(x) is p(1 - p)

<h3>How to compute E(x79)</h3>

The expected value of x79, E(x79) is calculated as:

$E(x^{79}) = \sum x^{79} * P(x)$

So, we have:

$E(x^{79}) = 0^{79} * (1- p) + 1^{79} * p$

Evaluate the exponents

$E(x^{79}) = 0 * (1- p) + 1 * p$

Multiply

$E(x^{79}) = 0 + p$

Add

$E(x^{79}) = p$

Hence, the value of E(x79) is p

Read more about probability distribution at:

brainly.com/question/15246027

5 0

3 years ago

Lucia knows the fourth term in a sequence is 55 and the ninth term in the same sequence is 90. Explain how she can find the comm

Andreyy89

Using the formula for the nth term of an arithmetic progression.
an = a + (n - 1)d
a(4) = a + 3d = 55
a(9) = a + 8d = 90
a(9) - a(4) => 5d = 35
d = 35/5 = 7.
From a(4): a = 55 - 3d = 55 - 3(7) = 55 - 21 = 34

a(2) = a + d = 34 + 7 = 41.

4 0

4 years ago

Solve the equation for the unknown variable b³ = 5,832

Llana [10]

All you would need to do for this equation is take the cubed root of 5,832

the answer ends up being b=18

8 0

3 years ago