Where does the graph of y = sin x from x = 0 to x = 2π start?
2 answers:
Answer:
The graph of y=sin x start from x-intercept.
B is correct.
Step-by-step explanation:
Given:
From
We need to find starting point of graph.
Graph will start when x=0
Put x = 0 into y = sin x
We get,
y = sin (0)
y = 0
Starting point is (0,0)
The value of y is 0.
It would be x-intercept of graph.
Hence, The graph of y=sin x start from x-intercept.
You might be interested in
AD is the diagonal of a 6 by 15 rectangle,
31.
Choice A
32.
Choice A
33.
7 - 4x = 7y
4x + 7y = -7
The parallel through (2,0) keeps the coefficients on x and y and just changes the constant:
4x + 7y = 4(2)+7(0)= 8
7y = -4x + 8
y = (-4/7) x + 8/7
Choice B
Answer:
F(x) = 2x^2 - 4x - 5
vertex? (1,-7)
range?
{y|y>=-7}
number of solutions?
Sorry I couldn’t find the answer, I hope this will do.
