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Free_Kalibri [48]
3 years ago
6

Where does the graph of y = sin x from x = 0 to x = 2π start?

Mathematics
2 answers:
Bad White [126]3 years ago
6 0

the graph starts at an x intercept.

navik [9.2K]3 years ago
4 0

Answer:

The graph of y=sin x start from x-intercept.

B is correct.

Step-by-step explanation:

Given: y=\sin x

From x=0\text{ to }x=2\pi

We need to find starting point of graph.

Graph will start when x=0

Put x = 0 into y = sin x

We get,

y = sin (0)

y = 0

Starting point is (0,0)

The value of y is 0.

It would be x-intercept of graph.

Hence, The graph of y=sin x start from x-intercept.

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