(-3 +6 i )(-3 - 6 i )
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Answer:
Step-by-step explanation:
A) From the order of the exercise we already know that the intersection points lies on the Y-axis, so its coordinates are P(0;y;0). In order to find it, we only need to substitute the equation 4x+4z=0 into the equation 4x+3y+4z=1. Then,
1=4x+3y+4z = 3y + (4x+4z)= 3y+0.
From the expression above it is easy to obtain that y=1/3, and the intersection point is P(0;1/3;0).
B) To obtain the parallel vector to both planes we use the cross product of the normal vector of the planes.
As we want a unit vector, we must calculate the modulus of u:
.
Thus, the wanted vector is . Therefore,
.
C) In order to obtain the vector equation of the intersection line of both planes, we just need to put together the above results.
where is a real number.