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Dimas [21]
3 years ago
10

Solve the following equation: x^3 -168 = [24(x-2)] / 2 PLEASE REPLY ASAP

Mathematics
1 answer:
Nataly_w [17]3 years ago
7 0
Hi Larry

x^3 - 168 = [ 24(x-2)] / 2
x^3 - 168 = (24x - 48)/2
x^3 - 168 = 12x - 24
Subtract 12x - 24 to both sides
x^3 - 168 - (12x - 24) = 12xx - 24 - (12x - 24)
x^3 - 12x - 144 = 0
Now, factor the left sides
(x - 6)(x^2 + 6x + 24) = 0
Set factors equal to 0
x - 6 = 0 or x^2 + 6x + 24 = 0
x = 0 + 6 or x^2 + 6x + 24 - 0
x = 6
Answer : X = 6

Good luck !
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