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Dimas [21]
3 years ago
10

Solve the following equation: x^3 -168 = [24(x-2)] / 2 PLEASE REPLY ASAP

Mathematics
1 answer:
Nataly_w [17]3 years ago
7 0
Hi Larry

x^3 - 168 = [ 24(x-2)] / 2
x^3 - 168 = (24x - 48)/2
x^3 - 168 = 12x - 24
Subtract 12x - 24 to both sides
x^3 - 168 - (12x - 24) = 12xx - 24 - (12x - 24)
x^3 - 12x - 144 = 0
Now, factor the left sides
(x - 6)(x^2 + 6x + 24) = 0
Set factors equal to 0
x - 6 = 0 or x^2 + 6x + 24 = 0
x = 0 + 6 or x^2 + 6x + 24 - 0
x = 6
Answer : X = 6

Good luck !
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Two decreased by a half of a number is 1/2 of the number
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Answer:  The number is:  "2" .
_______________________________________________________
The expression is:  2 − (½)x = (½)<span>x  ;
                </span>→<span> in which "x" is the "unknown number".
</span>_______________________________________________________
Explanation:
______________________________________________________
Given:  
_________________________________________________________
"Two decreased by a half of a number is one-half<span> of the number" ; 

Let "x" represent the "unknown number" for which we wish to solve;

Write the expression as:
_________________________________________________
" </span>2 − (½)x = (½)x " .
_________________________________________________
Note:  Add "(½)x" to EACH SIDE of the equation:
_________________________________________________
2 − (½)x + (½)x = (½)x + (<span>½)</span>x ;

to get:
_________________________________________________
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       ↔  1x = 2 ;
 
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Answer:  The number is:  " 2 " .
_________________________________________________
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