Answer:
x = -8/2
Step-by-step explanation:
To make the equation easier to work with, our first step will be to make all of our fractions have a common denominator. Both 2 and 4 are factors of 8, so that will be our common denominator.
Old Equation: 1/4x - 1/8 = 7/8 + 1/2x
New Equation (with common denominators): 2/8x - 1/8 = 7/8 + 4/8x
Now, we're going to begin to isolate the x variable. First, we're going to subtract 2/8x from both sides, eliminating the first variable term on one side completely.
2/8x - 1/8 = 7/8 + 4/8x
-2/8x -2/8x
__________________
-1/8 = 7/8 + 2/8x
We're one step closer to our x variable being isolated. Next, we're going to move the constants to the left side of the equation. To do this, we must subtract by 7/8 on both sides.
-1/8 = 7/8 + 2/8x
- 7/8 -7/8
______________
-1 = 2/8x
Our last step is to multiply 2/8x by its reciprocal in order to get the x coefficient to be 1. This means multiply both sides by 8/2.
(8/2) -1 = 2/8x (8/2)
The 2/8 and 8/2 cancel out, and you're left with:
-8/2 = x
I hope this helps!
Answer:
If it is 
then it is the solution 
because the square root of an expression multiplied by itself gives that expression.
Answer:
25 almost full boxes
Step-by-step explanation:
corresponding angles, therefore
m∠1 = m∠2 → m∠2 = 130°
vertical angles, therefore
m∠2 = m∠3 → m∠3 = 130°
If ∠1 and ∠2 are complementary, then m∠1 + m∠2 = 90°.
If ∠2 and ∠3 are complementary, then m∠2 + m∠3 = 90°
Therfore
Answer:
The histogram is right-skewed.
Step-by-step explanation:
The income of all households in the United States can be categorized as low, medium and high.
Not many people earn a high income. So the proportions of people decreases as the income increases.
Most of the people earn a medium income. So the mode of the data would be somewhere in the start of the the distribution.
There are many households that earn a low income. But this proportion is not more than the proportion of people earning low income.
So the histogram for income distribution will have a long right tail with maximum data at the starting point.
This implies that the histogram is right-skewed.
