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Effectus [21]
3 years ago
12

Multiplication between exponentiation number 648

Mathematics
1 answer:
JulijaS [17]3 years ago
4 0

Answer:

648 is the sum of consecutive prime numbers 317 and 331.

The sixth root of 648 begins with 2.941682753. Notice all the digits from 1 to 9 appear somewhere in those nine decimal places. OEIS.org states that 648 is the smallest number that can make that claim.

From Archimedes-lab.org I learned some powerful facts about the number 648:

16² – 17² + 18² – 19² + 20² – 21² +22² – 23² + 24² – 25² + 26² – 27² + 28² – 29² + 30² – 31² + 32² = 648

48² – 47² + 46² – 45² + 44² – 43² +42² – 41² + 40² – 39² + 38² – 37² + 36² – 35² + 34² – 33² = 648

(1^2)(2^3)(3^4) = 648

18² + 18²  = 648

(6^3) + (6^3) + (6^3) =648

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Print the puzzles or type the solution on this excel file: 10 Factors 2015-10-12

—————————————————————————————————

648 is a composite number.

Prime factorization: 648 = 2 x 2 x 2 x 3 x 3 x 3 x 3, which can be written 648 = (2^3) x (3^4)

The exponents in the prime factorization are 3 and 4. Adding one to each and multiplying we get (3 + 1)(4 + 1) = 4 x 5 = 20. Therefore 648 has exactly 20 factors.

Factors of 648: 1, 2, 3, 4, 6, 8, 9, 12, 18, 24, 27, 36, 54, 72, 81, 108, 162, 216, 324, 648

Factor pairs: 648 = 1 x 648, 2 x 324, 3 x 216, 4 x 162, 6 x 108, 8 x 81, 9 x 72, 12 x 54, 18 x 36, or 24 x 27

Taking the factor pair with the largest square number factor, we get √648 = (√324)(√2) = 18√2 ≈ 25.455844122…

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The ratio of girls to boys in Liza’s classroom is 5 to 4. How many girls are in her classroom if there is a total of 27 students
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Answer:

\boxed{\sf Number \ of \ girls \ in \ classroom =15}

Given:

Ratio of numbers of girls to boys = 5:4

Total number of students = 27

To Find:

Numbers of girls in classroom

Step-by-step explanation:

Let number of girls be 'x' and number of boys be 'y'

\sf \implies \frac{x}{y} = \frac{5}{4} \ \ \ \ \ \ \ \ \ \ .....Eq_{1} \\ \\ \sf \implies x + y = 27 \ \ \ \ \ \ \ \ \ \ .....Eq_{2}

\sf  \bold{ \large From \ Eq_{1} :} \\ \sf  \implies \frac{x}{y} =  \frac{5}{4}   \\   \\ \sf Taking \:  the \:  reciprocal  \: of  \: both  \: sides:\\  \sf  \implies  \frac{y}{x}  =  \frac{4}{5}  \\  \\  \sf Multiply \:  both \:  sides  \: by \:  x: \\  \sf \implies y =  \frac{4}{5} x

\sf  \bold{ \large Substituting \ value \ of \ y \ in \ Eq_{2},} \\  \bold{ \large we \ get:} \\ \sf \implies x +  \frac{4}{5} x = 27 \\  \\  \sf Put  \: each \:  term \:  in  \: x +  \frac{4}{5} x \: over \:  the  \: common   \\ \sf denominator  \: 5: \\  \sf \implies \frac{5x}{5}  +  \frac{4x}{5}  = 27 \\  \\  \sf  \frac{5x}{5}  +  \frac{4x}{5}  =  \frac{5x + 4x}{5}:  \\  \sf  \implies \boxed{ \sf \frac{5x + 4x}{5}} = 27 \\  \\  \sf 5x + 4x = 9x :  \\  \sf \implies  \frac{ \boxed{ \sf 9x}}{5}  = 27 \\  \\  \sf Multiply  \: both  \: sides  \: of \:  \frac{9x}{5}  = 27 \: by \:  \frac{5}{9}  :  \\  \sf \implies  \frac{9x}{5}  \times   \boxed{\frac{5}{9}}  = 27 \times  \boxed{ \frac{5}{9} } \\  \\  \sf \frac{ \cancel{9} \times  \cancel{5}}{ \cancel{5} \times  \cancel{9}} x = x :  \\  \sf \implies \boxed{x} = 27 \times  \frac{5}{9}  \\  \\  \sf 3 \times  \cancel{9} \times  \frac{5}{ \cancel{9}}  = 5 \times 3 :  \\   \sf \implies x =  \boxed{5 \times 3} \\  \\  \sf 5 \times 3 = 15 :  \\  \sf \implies x = 15

So,

Numbers of girls in classroom = 15

6 0
4 years ago
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