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blagie [28]
3 years ago
15

Suppose you were looking at the histogram of the incomes of all of the households in the United States. Do you think that the hi

stogram would be bell shaped? Skewed to the left or right?
Mathematics
1 answer:
seraphim [82]3 years ago
8 0

Answer:

The histogram is right-skewed.

Step-by-step explanation:

The income of all households in the United States can be categorized as low, medium and high.

Not many people earn a high income. So the proportions of people decreases as the income increases.

Most of the people earn a medium income. So the mode of the data would be somewhere in the start of the the distribution.

There are many households that earn a low income. But this proportion is not more than the proportion of people earning low income.

So the histogram for income distribution will have a long right tail with maximum data at the starting point.

This implies that the histogram is right-skewed.

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Solve equation<br>8-3(p-4)=2p
LenKa [72]

Answer:

ok the answer is: p=-4

Step-by-step explanation:

First you distribute 3 times p-4 and get  8-3p+12=2p then you add 12 plus 8 and get 20 then you have 20-3p=2p you have to add 3p on both sides and you get 20= -5p you divide and get p= -4

6 0
3 years ago
A shirts price was $32, on 6% mark, what is the new price of the shirt
allochka39001 [22]

Answer:

19.20

Step-by-step explanation:

.6 is 6%. X 32

8 0
3 years ago
Read 2 more answers
The delivery times for all food orders at a fast-food restaurant during the lunch hour are normally distributed with a mean of m
UkoKoshka [18]

Answer:

Let X the random variable that represent the delivery times of a population, and for this case we know the distribution for X is given by:

X \sim N(14.7,3.7)  

Where \mu=14.7 and \sigma=3.7

Since the distribution of X is normal then we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And we have;

\mu_{\bar X}= 14.70

\sigma_{\bar X} =\frac{3.7}{\sqrt{40}}= 0.59

Step-by-step explanation:

Assuming this question: The delivery times for all food orders at a fast-food restaurant during the lunch hour are normally distributed with a mean of 14.7 minutes and a standard deviation of 3.7 minutes. Let R be the mean delivery time for a random sample of 40 orders at this restaurant. Calculate the mean and standard deviation of \bar X Round your answers to two decimal places.

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the delivery times of a population, and for this case we know the distribution for X is given by:

X \sim N(14.7,3.7)  

Where \mu=14.7 and \sigma=3.7

Since the distribution of X is normal then we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And we have;

\mu_{\bar X}= 14.70

\sigma_{\bar X} =\frac{3.7}{\sqrt{40}}= 0.59

4 0
3 years ago
What’s the solution of y= 3x-1 and y= 3x+4
julia-pushkina [17]

Step-by-step explanation:

solution ? you mean where both lines cross each other ?

these are 2 parallel lines (same slope, but different y-intercept), so they never cross each other.

there is no solution.

formally :

3x - 1 = 3x + 4

-1 = 4

this is wrong. therefore there is no solution.

3 0
2 years ago
The ratio of girls to boys in Liza’s classroom is 5
alexira [117]
There are 15 girls in the classroom
6 0
3 years ago
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