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Pie
2 years ago
15

The ratio of boys to girls is 15:11 .if boys are 435 find the number of girls​

Mathematics
1 answer:
Alona [7]2 years ago
3 0

Answer:

Girls = 319

Step-by-step explanation:

Given

Boys: Girls = 15:11

Required

Find Girls, when Boys = 435

Substitute 435 for Boys

435: Girls = 15:11

Express as fraction

\frac{Girls}{435} = \frac{11}{15}

Multiply through by 435

435 * \frac{Girls}{435} = \frac{11}{15}* 435

Girls = \frac{11}{15}* 435

Girls = \frac{11* 435}{15}

Girls = \frac{4785}{15}

Girls = 319

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Sketch the curve represented by the parametric equations (indicate the orientation of the curve), and write the corresponding re
raketka [301]

Answer:

(See explanation below for further details).

Step-by-step explanation:

Let be a parametric curve represented by x = 3\cdot t - 5 and y = 5\cdot t + 1, where t is the parametric variable.

The curve is represented graphically with the help of a graphing tool, whose outcome is included in the image attached below. The corresponding rectangular equation is found by eliminating t of each equation.

t = \frac{x+5}{3} and t = \frac{y-1}{5}

\frac{x+5}{3} = \frac{y-1}{5}

5\cdot (x+5) = 3\cdot (y-1)

5\cdot x +25 = 3\cdot y - 3

5\cdot x -3\cdot y = -28

The parametric equations represents a linear function (first-order polynomial).

8 0
3 years ago
The first term of an arithmetic sequence is -3 and the fifteenth term is 53. What is the common difference of the sequence?
Maru [420]

C: 4 is the right answer

Step-by-step explanation:

Given

a1 = -3

a15 = 53

We know that explicit formula for the arithmetic sequence is:

a_n=a_1+(n-1)d

For the 15th, term it will be

a_{15}=-3+(15-1)d\\53=-3+14d

Adding 3 on both sides

53+3 = -3+3 + 14d\\56 = 14d

Dividing both sides by 14

\frac{56}{14}=\frac{14d}{14}\\d=4

Hence,

C: 4 is the right answer

Keywords: Arithmetic sequence, Common Difference

Learn more about arithmetic sequence at:

  • brainly.com/question/12896802
  • brainly.com/question/12973601

#LearnwithBrainly

4 0
2 years ago
Hey lol help lol
Gwar [14]

Answer:

Just cut the tree down and stick it to the teachers.

Step-by-step explanation:

7 0
2 years ago
In ΔNLM, if m∠M=(4x-4)°, m∠L=(3x+12)°, and m∠N=(6x+3)°, what is x?
GarryVolchara [31]

Answer:

  x = 13

Step-by-step explanation:

The sum of angle measures in a triangle is 180°.

  m∠M + m∠L + m∠N = 180°

  (4x-4)° + (3x+12)° + (6x+3)° = 180°

  13x +11 = 180 . . . . . . collect terms, divide by °

  13x = 169 . . . . . . . . . subtract 11

  x = 13 . . . . . . . . . . . . . divide by 13

5 0
2 years ago
R= m/2 (c + K) for k
Wewaii [24]

Answer:

                  \bold{K=\frac{2r}m-c=\frac{2r-cm}m}

Step-by-step explanation:

\bold{r= \frac m2 (c + K)}\\^{\div\frac m2}\qquad^{\div\frac m2}\\ \bold{r\cdot\frac2m=c+K}\\{}\ ^{-c}\qquad^{-c}\\\bold{\frac{2r}m-c=K}

Or if you mean r= m/[2(c + K)]

\bold{\quad r\ =\ \frac m{ 2(c + K)}}\\^{\cdot(c+K)}\quad^{\cdot(c+K)}\\ \bold{r(c+K)=\frac m2}\\{}\qquad ^{\div r}\qquad^{\div r}\\\bold{c+K=\frac m2\cdot\frac1r}\\{}\quad^{-c}\qquad^{-c}\\\bold{K=\frac m{2r}-c}

5 0
2 years ago
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