The total number of ways by words are formed is 35 ways.
According to the statement
We have given that the 5 letters and we have to make word from them and the letters are repeated as equal to letters in given words.
And we have to find the possible ways.
So, The given words are:
TEXAS and MEXICO
Here X = 2 and E = 2 and all other words are one time used words.
We can find possible ways by use of combination and permutation.
So,
Total number of ways = 
here 3 because three letters are not repeatable and 2 letters are repeated for 2 times.
So,
Total number of ways =
Total number of ways = 
Total number of ways = 
Total number of ways = 15 + 20
Total number of ways = 35.
So, The total number of ways by letters are formed is 35 ways.
Learn more about combination and permutation here
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Choose the three shapes that have and Area of 36 square centimeters
Step-by-step explanation:
D = # of dimes
n= # of nickles
d + n = 34 so d = 34 - n
.10d + .05n = 2.05
substitute d = 34 - n into .10d + .05n = 2.05
.10d + .05n = 2.05
.10( 34 - n) + .05n = 2.05
3.4 - .1n + .05n = 2.05
-.05n = -1.35
n = 27
d = 34 - n
d = 34 - 27
d = 7
answer
<span>she received 7 dimes and 27 nickels</span>
It is written as 35% or 0.35
Hope this helps!! :)
He can give at most 2 adult haircuts with the remaining time
<h3>How many adult haircuts at most can he give with the remaining time? </h3>
The inequality is given as:
0.75C + 1.25A <= 7
Also, we have
C = 5
Substitute C = 5 in 0.75C + 1.25A <= 7
0.75 * 5 + 1.25A <= 7
Evaluate the product
3.75 + 1.25A <= 7
Evaluate the like terms
1.25A <= 3.25
Divide by 1.25
A <= 2.6
Rewrite as
A < 3
Hence, he can give at most 2 adult haircuts with the remaining time
Read more about inequalities at:
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<u>Complete question</u>
Horace is a professional hair stylist. Let C represent the number of child haircuts and A represent the number of adult haircuts that Horace can give within 7 hours. 0.75C + 1.25A <= 7
Horace gave 5 child haircuts.
How many adult haircuts at most can he give with the remaining time?
