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dmitriy555 [2]
3 years ago
8

Where do i graph it

Mathematics
2 answers:
Anuta_ua [19.1K]3 years ago
7 0
(-5,-10)E
(-5,-3)F
(-3,-10)G
Airida [17]3 years ago
5 0
As seen in attachment, the reflection across the x-axis is just you flip the graph over x-axis (horizontal line).

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A pair of Descartes jeans costs $120. If the tax is 13%, how much does the pair of jeans cost including tax?
ivanzaharov [21]

Answer:

$135.60

Step-by-step explanation:

120*13%=15.6

15.60+120.00=$135.60

5 0
3 years ago
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3. You are selling hot cocoa at an
Liono4ka [1.6K]

Answer:

you need to sell 60 cups

Step-by-step explanation:

48÷0.80= 60 cups

hope it helps!

please mark me brainliest

5 0
3 years ago
Pls help me answer the question and if you don't know, pls don't answer. thank you!
Damm [24]
The answer is 162in2 to its orbit
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3 years ago
Statistics question about random probability Cheese pastureized or Raw MilkA cheese can be classified as either raw-milk or past
blsea [12.9K]

Answer:

(a) Two cheeses are chosen at random. the probability that both cheeses are pasteurized is Pr(PP) = 0.82 x 0.82 = 0.6724 to 4 decimal places)

(b) Four cheeses are chosen at random. The probability that all four cheeses are pasteurized is Pr(PPPP) = 0.82 x 0.82 x 0.82 x 0.82 = 0.4521 to 4 decimal places

(c) What is the probability that at least one of four randomly selected cheeses is raw-milk is Pr(RPPP) Or Pr(RRPP) Or Pr(RRRP) Or Pr(RRRR)

= 0.1269 to 4 decimal places

It would not be unusual that at least one of four randomly selected cheeses is raw-milk, because the probability have a value between 0 and 1

Step-by-step explanation:

If is given that 80% of the cheese is classified as pasteurized.

It then implies that 20% of the cheese is classified as Raw-milk

Probability of pasteurized cheese is 0.82(Denoted by Pr(P))

Probability of raw-milk cheese is 0.18(Denoted as Pr(R))

(a) Two cheeses are chosen at random. the probability that both cheeses are pasteurized is Pr(PP) = 0.82 x 0.82 = 0.6724 to 4 decimal places)

(b) Four cheeses are chosen at random. The probability that all four cheeses are pasteurized is Pr(PPPP) = 0.82 x 0.82 x 0.82 x 0.82 = 0.4521 to 4 decimal places

(c) What is the probability that at least one of four randomly selected cheeses is raw-milk is Pr(RPPP) + Pr(RRPP) + Pr(RRRP) + Pr(RRRR)

(0.18 x 0.82 x 0.82 x 0.82) + (0.18 x 0.18 x 0.82 x 0.82) + (0.18 x 0.18 x 0.18 x 0.82) + (0.18 x 0.18 x 0.18 x 0.18) = 0.1269 to 4 decimal places

3 0
3 years ago
Helppppp me I am stuck help me plzz
soldi70 [24.7K]

Answer:

espero sirva qwq

Step-by-step explanation:

4= 0.56666666666

5=1.66666666667

6=1.375

7=1.425

8=0.92857142857

9=1.666666667

10=1.44444444444

11=0.825

6 0
3 years ago
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