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Marina CMI [18]
3 years ago
9

Please help. Don’t answer unless you’re 100% sure.

Mathematics
1 answer:
zavuch27 [327]3 years ago
6 0

Answer:

A- mercury and helium

b- 1034.86

Step-by-step explanation:

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The mayor of a town places a map of the town on a coordinate grid with Town Hall at the point (0,0) and with each unit represent
Lorico [155]

Answer:

Given that the question rightly asks the amount it cost to drive from Smithville to Jones City, we have;

The question rightly asks the amount it cost to drive from Smithville to Jones City is approximately $7.209

Step-by-step explanation:

The coordinates of Smithville is (-25, 10)

The coordinates of Jones City is (15, 12)

The cost of driving a car for a mile = $0.18

Therefore, the distance from Smithville to Jones City is given by the formula for the distance, l, between two points with coordinates as follows;

l = \sqrt{\left (y_{2}-y_{1}  \right )^{2}+\left (x_{2}-x_{1}  \right )^{2}}

Where;

(x₁, y₁) = (-25, 10) and (x₂, y₂) = (15, 12)

l = \sqrt{\left (12-10  \right )^{2}+\left (15-(-25)  \right )^{2}} = 2 \cdot \sqrt{401}

The distance from Smithville to Jones City = 2·√401 ≈ 40.05 miles

The amount, A, it cost to drive from Smithville to Jones City a distance of approximately 40.05 miles is therefore given as follows;

A = 40.05 miles × $0.18 ≈ $7.209

8 0
3 years ago
If x < 5, then which of the following must be true?
pychu [463]

Answer:

2 answers

Step-by-step explanation:

8 0
4 years ago
Solve for x. Round to the nearest tenth of a degree, if necessary.​
MissTica

Answer:

x ≈ 54.8°

Step-by-step explanation:

Using the tangent ratio in the right triangle

tan x = \frac{opposite}{adjacent} = \frac{PQ}{QR} = \frac{7.1}{5} , then

x = tan^{-1} (\frac{7.1}{5} ) ≈ 54.8° ( to the nearest tenth )

4 0
3 years ago
Find the value of x if 81=3x
Alex Ar [27]

Answer:

<em>here </em><em> </em><em>,</em>

<em>8</em><em>1</em><em>=</em><em>3</em><em>x</em>

<em>or </em><em>,</em><em> </em><em>8</em><em>1</em><em>/</em><em>3</em><em>=</em><em>x</em>

<em>or,</em><em>2</em><em>7</em><em>=</em><em>x</em>

<em>hence </em><em>,</em><em>the </em><em>value </em><em>of </em><em>x=</em><em>2</em><em>7</em>

4 0
3 years ago
Read 2 more answers
p is the point on the line 2x+y-10=0 such that the length of OP, the line segment from the origin o to p is a minimum. find the
REY [17]
Coolio

alright, so the disatnce formula is
D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

solve for y in the equation given on top
2x+y-10=0
y=10-2x
ok
so (x1,y1)=(0,0), the first point
(x2,y2)=(x,10-2x)
so subsitute to get

D=\sqrt{(x-0)^2+(10-2x-0)^2}
D=\sqrt{(x)^2+(10-2x)^2}
D=\sqrt{x^2+4x^2-40x+100}
D=\sqrt{5x^2-40x+100}
find the miniumum
we only need to minimize what is under the square root so
take the derivitive of 5x²-40x+100
that is 10x-40
it is 0 at x=4
when x<4, the derivitive is negative
when x>4, the derivitive is positve
goes from negative to positive
so it is a minimum

at x=4
find y
y=10-2x
y=10-2(4)
y=10-8
y=2

(4,2)
find min distance

D=\sqrt{(x-0)^2+(y-0)^2}
D=\sqrt{(4-0)^2+(2-0)^2}
D=\sqrt{(4)^2+(2)^2}
D=\sqrt{16+4}
D=\sqrt{20}
D=2\sqrt{5}



the point, P, is (4,2) and the minimum distance is 2√5
5 0
4 years ago
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