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2 years ago

10

How to find the hypotenuse of a right angle

2 answers:

mars1129 [50]2 years ago

8 0

Answer: a^2+b^2=c^2 and c^2 is supposed to be the hypotenuse

Step-by-step explanation: The Pythagorean Theorum is a to help find the hypotenuse or any other side in a right triangle. The formula is a^2+b^2=c^2

Ray Of Light [21]2 years ago

7 0

You square the length of both legs, and add the 2 squares together. You then find the square root of the sum, and that is the length of the hypotenuse

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3 years ago

Write the standard form of the equation of the circle that passes through the point

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Answer:

The standard form of the equation of the circle is $x^2+y^2=1$ .

Step-by-step explanation:

A circle is the set of points in a plane that lie a fixed distance, called the radius, from any point, called the center.

The equation of a circle in standard form is

$(x-h)^2+(y-k)^2=r^2$

where <em>r</em> is the radius of the circle, and <em>h</em>, <em>k</em> are the coordinates of its center.

When the center of the circle coincides with the origin $h=k=0$ , so

$(x-0)^2+(y-0)^2=r^2\\x^2+y^2=r^2$

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Step-by-step explanation:

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2 years ago

Find the value of x such that the area of a triangle whose vertices have coordinates (6, 5), (8, 2) and (x, 11) is 15 square uni

Serjik [45]

Answer:

$x =12\ or\ -8$

Step-by-step explanation:

Given

$(x_1,y_1) = (6,5)$

$(x_2,y_2) = (8,2)$

$(x_3,y_3) = (x,11)$

$Area = 15$

Required

Find x

The area is calculated as thus:

$Area = \frac{1}{2}|x_1(y_2 - y_3) + x_2(y_3 - y_1) + x_3(y_1 - y_2)|$

Substitute values

$15 = \frac{1}{2}|6*(2 - 11) + 8*(11 - 5) + x(5 - 2)|$

$15 = \frac{1}{2}|6*(-9) + 8*(6) + x(3)|$

$15 = \frac{1}{2}|-54 + 48 + 3x|$

$15 = \frac{1}{2}|-6 + 3x|$

Multiply through by 2

$2 * 15 = \frac{1}{2}|-6 + 3x| * 2$

$30 = |-6 + 3x|$

Remove absolute sign

$30 = -6 + 3x\ or\ -30 = -6 + 3x$

Add 6 to both sides

$36 = 3x\ or\ -24 = 3x$

Divide by 3

$12 = x\ or\ -8 = x$

$x =12\ or\ -8$

<em>So, the coordinates are (-8, 11) or (12,11)</em>

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2 years ago