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vlada-n [284]
3 years ago
10

How to find the hypotenuse of a right angle

Mathematics
2 answers:
mars1129 [50]3 years ago
8 0

Answer: a^2+b^2=c^2 and c^2 is supposed to be the hypotenuse

Step-by-step explanation: The Pythagorean Theorum is a to help find the hypotenuse or any other side in a right triangle. The formula is a^2+b^2=c^2

Ray Of Light [21]3 years ago
7 0

You square the length of both legs, and add the 2 squares together. You then find the square root of the sum, and that is the length of the hypotenuse

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14 POINTS ASAP WHAT IS THE MEASURE OF ANGLE A
sashaice [31]
Wow...we have lots of numbers to go through.  we know that a 6 sided figure is a hexagon and the interior angles add up to be 720°. so.....

∠A + ∠B + ∠ C + ∠D + ∠E + ∠F = 720°
(x - 60) + (x - 40) + 130 + 120 + 110 + (x - 20) = 720
3x + 240 = 720      (combined all like terms)
3x = 480                (subtracted 240 from both sides)
x = 160                  (divided both sides by 3)

put the value of x into ∠A  (x - 60) = 160 - 60 = 100

∠A = 100°
7 0
3 years ago
Does Anybody know this? Find the area of the shaded sector
Sunny_sXe [5.5K]

Step-by-step explanation:

your teacher was very nice and warned you about the trap in the question.

so, really, what do we have to do ?

a full circle represents 360°.

the shaded sector is the full circle minus the white sector !

this is the same as directly calculating the shaded sector for 360-75 = 285°.

so, the area of a circle is

pi×r²

in our case

pi×20² = 400pi

the needed fraction of the whole circle is either

75/360, if we want to subtract it for the solution

or

285/360, if we want to calculate the solution directly.

both lead to the same result.

400pi×360/360 - 400pi×75/360 =

= 400pi × 285/360 = 10pi × 285/9 = 2850pi/9 =

= 316.6666666...pi ≈ 316.7pi

8 0
2 years ago
Describe how to use the Vertical Line Test and what it can tell us.
tia_tia [17]

Answer: To use the Vertical Line Test, you draw a line parallel to the y-axis for any value of x and if the line intersects the curve graphed, then the curve is not a function. We use Vertical Line Tests to see if curves are functions.

3 0
3 years ago
5/42 in simplest forms
natka813 [3]
This is in simplest form.
4 0
3 years ago
Read 2 more answers
Can someone help me with this please
d1i1m1o1n [39]

9514 1404 393

Answer:

  1. attendance (y), time (x)

  2. 1,2: increasing; 3: constant; 4: decreasing

  3. attendance increases, remains constant, then decreases

  4. increasing; pre-heating the oven

Step-by-step explanation:

It is always difficult to read the mind of the author of questions like these. Usually, specific wording is expected. If your curriculum material has examples you can copy from, you should do that.

__

1. The variables and what they stand for are listed on the axes of the graph. The y-variable stands for attendance. The x-variable stands for time. It isn't clear whether the desired answer is "y and x" or "attendance and time".

__

2. The graph slopes upward in intervals 1 and 2. It can be described as "increasing."

The graph remains level in interval 3. It can be described as "constant."

The graph slopes downward in interval 4. It can be described as "decreasing."

__

3. The attendance is adequately described in question 2. Attendance increases, remains constant, then decreases. It isn't clear how general or specific the answer is supposed to be.

__

4. The graph of the function is "increasing." We don't know if the indicated temperature is the temperature of the bread, the oven, or the room containing the oven. If we assume the indicated temperature is that of the oven, we expect an increase during the oven pre-heat interval.

If the indicated temperature is that of the bread, then the increase would be following insertion of the bread into the oven.

4 0
2 years ago
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