The mean number of people per day visiting an art show in July was 110. If

Wrapping paper comes in 3 colors, on either a regular roll or an extra wide roll, and with or without a pattern. How many combin

VladimirAG [237]

Answer:

12 combinations

Step-by-step explanation:

The sample space is the set of all possible combinations. In this case, there are 3 possible colors, 2 possible widths and 2 possible patterns (with or without), The number of possible combinations is given by multiplying the number of options for each trait:

$n=3*2*2\\n=12\ combinations$

There are 12 possible combinations.

3 0

3 years ago

Can someone please help me with this?

lutik1710 [3]

Answer:

(-78/29, -619/29)

Step-by-step explanation:

Since both equations are equal to y we can set them equal to each other

15x+19 = 1/2x - 20

Subtract 1/2x from each side

15x -1/2x +19 = -20

Subtract 19 from each side

14 1/2 x +19-19 = -20-19

Changing to an improper fraction

29/2 x = -38

Multiply each side by 2/29

x = 2/29 * -38

x = -78/29

Now find y

y = 1/2x - 20

y = 1/2 (-78/29) -20

y = -39/29 - 20

Get a common denominator

=-39/20 - 580/29

= -619/29

-39/29 -580/29

8 0

3 years ago

A garden box has a perimeter of 18½ feet. If the length is 5 feet, what is the area of the garden box?

Travka [436]

Answer:

$area=\frac{85}{4}feet^{2}$

Step-by-step explanation:

1. Approach

Since it is given that the garden box is a rectangle, then the opposite sides are congruent. One can use this to their advantage, by setting up an equation that enables them to solve for the width of the rectangle. After doing so, one will multiply the width by the given length and solve for the area.

2. Solve for the width

It is given that the garden box is a rectangle. As per its definition, opposite sides in a rectangle are congruent. The problem gives the length and the perimeter of the rectangle, therefore, one can set up an equation and solve for the width.

$perimeter=18\frac{1}{2}\\\\length=5$

$2(length+width)=perimeter$

Substitute,

$2(5+width)=18\frac{1}{2}$

Conver the mixed number to an improper fraction. This can be done by multiplying the "number" part of the mixed number by the denominator of the fraction. Then add the result to the numerator.

$2(5+width)=\frac{37}{2}$

Inverse operations,

$2(5+width)=\frac{37}{2}\\/2\\\\5+width=\frac{37}{4}\\-5\\\\width=\frac{17}{4}$

3. Solve for the area

Now that one has solved for the width of the box, one must solve for the area. This can be done by multiplying the length by the width. Since the width is a fraction, one must remember, that when multiplying an integer by a fraction, one will multiply the integer by the numerator (the top of the fraction), and then simplify by reducing the fraction, if possible. Reducing the fraction is when one divides both the numerator and the denominator by the GCF (Greatest Common Factor).

$length=5\\\\width = \frac{17}{4}$