5m+2m+2 = 23
7m=21 , So:: m=21:7
m=3
Okay so 6.25 a student then it goes to 4.50 for 15 more students at 70 students its 358.75 now it drops another 1.75 so it would be 368.75 for 80 students so the equation is 4.48 x 80 = 368.75. enjoy :D
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Answer:
C, A, A
Step-by-step explanation:
In general, you ...
- identify the coefficients of one of the variables
- swap them, and negate one of them
- multiply the corresponding equations by the "adjusted" coefficients.
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In problem 1, the x-coefficients are 8 and 2. A common factor of 2 can be removed so that we're dealing with the numbers 4 and 1. Assuming we want to multiply one of the equations by 1, leaving it unchanged, the value we want to multiply by will be -4. After we swap the coefficients, that multiplier is associated with equation 2:
multiply equation 2 by -4 . . . (eliminates x)
Likewise, the y-coefficients in problem 1 are -1 and 3. Again, if we want to multiply one of the equations by 1, leaving it unchanged, the coefficient we will change the sign of is -1 (becomes 1). After we swap the coefficients, the multiplier 3 is associated with equation 1:
multiply equation 1 by 3 . . . (eliminates y)
These two choices are B and A, respectively, so the one that does NOT work for problem 1 is choice C, as indicated below.
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The other problems are worked in a similar fashion.
Amount= Deposit or initial amount ( 1+ percent increase) ^period of time
So Amount= 50(1+0.1)^3
= 50(1.1)^3
= 50(1.331)
=66.55
So she will have $66.55 in 3 years.
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