Question

Factorise 4a^2+b^2-4ab-8a+4b+4​

Answer 1

Answer:

The factorized form of the given expression is  $4 [(a-1)^2 - b(a - 1 + \frac{b}{4})]$

Step-by-step explanation:

Given;

4a² + b²  -  4ab  -  8a +  4b   + 4

This expression is factorized as follows;

(4a²  -  8a  + 4)  +  (b² -  4ab + 4b)

(4a² - 4a - 4a + 4)  + b² - 4b(a - 1)

(4a - 4)(a - 1) + b² - 4b(a - 1)

(4a - 4)(a - 1) -  4b(a - 1) + b²

4(a - 1)(a - 1)   -  4b(a - 1) + b²

4(a - 1)²  - 4b(a - 1 + b/4)

$4(a- 1)^2 - 4b(a - 1 + \frac{b}{4} )\\\\4 [(a-1)^2 - b(a - 1 + \frac{b}{4})]$