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Vsevolod [243]
3 years ago
9

Tim has two spinners , spinnerA and spinner B. Each spinner can only land on red or blue . The probability that spinner A will l

and on red is 0.5. The probability that spinnerB will land on red is 0.6. Tim spins spinner A once and he spins spinnerB once. He does this a number of times . The number of times both spinners land on red is 84. Workout an estimate for the no of time both spinners land on blue.
Mathematics
1 answer:
Ganezh [65]3 years ago
4 0

Answer:

52

Step-by-step explanation:

<u>Spinner A</u>

  • Probability of red = 0.5,
  • Probability of blue = 0.5

<u>Spinner B</u>

  • Probability of red = 0.6,
  • Probability of blue = 0.4

<u>Probability of both A and B land on red: </u>

  • 0.5*0.6= 0.3

<u>Number of attempts to get outcome of 84 red on both spinners is:</u>

  • 84/0.3= 260

<u>Probability of both spinners land on blue:</u>

  • 0.5*0.4= 0.2

<u>Estimated number of both spinners land on blue:</u>

  • 260*0.2= 52  
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So we know that 100 grams MgCl2 to mol = 1.0503 mol.

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