- 3 (w + 5) 4wSimplify
2 answers:
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The vertex-form equation is
y = a(x+1)² -16
Putting in the y-intercept values, we have
-15 = a(0+1)² -16
1 = a . . . . . . . . . . . add 16
Then the x-intercepts can be found where y=0.
0 = (x+1)² -16
16 = (x+1)²
±4 = x+1
x = -1 ± 4 = {-5, 3}
y = a(x+1)² -16
Putting in the y-intercept values, we have
-15 = a(0+1)² -16
1 = a . . . . . . . . . . . add 16
Then the x-intercepts can be found where y=0.
0 = (x+1)² -16
16 = (x+1)²
±4 = x+1
x = -1 ± 4 = {-5, 3}
Answer:
5x + 3y = 13 parallel.
6x - 10y = 7 perpendicular.
Step-by-step explanation:
Two lines with slopes and
are parallel when
and are perpendicular when
Now determine the slope of all the lines
The line jk passes through the points
(-5,5) and (1,-5) so its slope is
To determine the slope of the lines in the blue rectangles, isolate y from each one and the coefficient of x is the slope
5x-3y = 8 ------> y = (5/3)x + 8/3 ------> slope 5/3
Neither parallel nor perpendicular.
6x+10y = 11 ------> y = (-6/10)x + 11/10 = (-3/5)x + 11/10 ------> slope -3/5
Neither parallel nor perpendicular.
5x + 3y = 13 ------> y = (-5/3)x + 13/3 ------> slope -5/3
This line is parallel
6x - 10y = 7 ------> y = (6/10)x - 7/10 = (3/5)x -7/10 ------> slope 3/5
Since (-5/3)(3/5) = -1 this line is perpendicular.