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3 years ago

How do you find the area of this triangle ?

Mathematics

1 answer:

marin [14]3 years ago

6 0

Multiply the base which is 18.65 and multiply it by the height which is 9 3/10 and then multiply by half and that estimates to B. 90 cm

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Find any 5 rational numbers between; a) -1 and 2 b) −3 8 −5 14

kap26 [50]

Answer:

Step-by-step explanation:

Hello,

You can list the following ones which are correct for a), b) and c)

$\boxed{\sf \bf \ \ 1, \dfrac{1}{2}, \dfrac{1}{3},\dfrac{1}{4},\dfrac{1}{5} \ \ }$

Thanks

4 0

3 years ago

11-15 pls help thanks

AlekseyPX

What do I need to solve :)

7 0

3 years ago

The answer to c plz

NikAS [45]

Answer:

≈ 30.63 cm²

Step-by-step explanation:

The shaded area is calculated by subtracting the area of the inner circle from the area of the outer circle.

outer circle has radius = 8 ÷ 2 = 4 and inner circle has radius = 5 ÷ 2 = 2.5

shaded area = πr₁² - πr₂² (r₁ is outer and r₂ is inner )

A = π (4² - 2.5²)

= π(16 - 6.25) = 9.75π ≈ 30.63 cm²

5 0

3 years ago

Find the length of the curve. R(t) = 7t, 3 cos(t), 3 sin(t) , −2 ≤ t ≤ 2

Leviafan [203]

we are given

$r(t)=(7t,3cos(t),3sin(t))$

we can find x , y and z

$x=7t,y=3cos(t),z=3sin(t))$

now, we can use arc length formula

$L=\int\limits^a_b {\sqrt{(x')^2+(y')^2+(z')^2} } \, dt$

now, we can find derivative

$x'=7,y'=-3sin(t),z'=3cos(t))$

now, we can plug values

and we get

$L=\int _{-2}^2\sqrt{7^2+\left(-3\sin \left(t\right)\right)^2+\left(3\cos \left(t\right)\right)^2}dt$

$L=\int _{-2}^2\sqrt{7^2+9}dt$

$=\sqrt{58}\cdot \:2-\left(-2\sqrt{58}\right)$

$L=4\sqrt{58}$ ...........Answer

8 0

3 years ago

Write the equation of a line, in slope-intercept form, that has a slope of m=9 and passes through the point (4, 31)

Darina [25.2K]

Answer:

9x-y = 5

Step-by-step explanation:

Equation of line in slope intercept form:

y-y1 = m*(x-x1), m=9, (x1,y1)=(4,31)

y-31 = 9*(x-4)

y-31 = 9x-36

9x-y = 36-31

9x-y = 5

4 0

2 years ago