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3 years ago

How do you find the area of this triangle ?

Mathematics

1 answer:

marin [14]3 years ago

6 0

Multiply the base which is 18.65 and multiply it by the height which is 9 3/10 and then multiply by half and that estimates to B. 90 cm

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How do you prove this?

frozen [14]

Answer:

Show ΔBCD ≅ ΔGFE, so ∠C ≅ ∠F. Base angle of an isosceles triangle are congruent, so ΔACF is isosceles.

Step-by-step explanation:

Informally, subtract DE from CE and DF. This will show CD ≅ EF.

Then ΔBCD ≅ ΔGFE by the HL theorem for right triangles.

Corresponding parts of congruent triangles are congruent, namely the angles C and F.

Since base angles of ΔACF are congruent, it is isosceles.

3 0

3 years ago

What is thw equivalent ratio to 204/306

sergey [27]

I believe it would just be 102/153.

3 0

3 years ago

HELP WILL MARK BRAINLEIST

omeli [17]

Answer: k=3

Step-by-step explanation:

33/99 divide top and bottom by 11

33/99divided by 11/11

=3/9

7 0

3 years ago

Read 2 more answers

Mrs Low has some money to buy plates and bowls for her new house.

jekas [21]

Answer:

78=p

$150

$20

6 bowls

Step-by-step explanation:

8 0

3 years ago

The miles-per-gallon rating of passenger cars is a normally distributed random variable with a mean of 33.8 mpg and a standard d

EleoNora [17]

Answer:

The probability that a randomly selected passenger car gets more than 37.3 mpg is 0.1587.

Step-by-step explanation:

Let the random variable <em>X</em> represent the miles-per-gallon rating of passenger cars.

It is provided that $X\sim N(\mu=33.8,\ \sigma^{2}=3.5^{2})$ .

Compute the probability that a randomly selected passenger car gets more than 37.3 mpg as follows:

$P(X>37.3)=P(\frac{X-\mu}{\sigma}>\frac{37.3-33.8}{3.5})$

$=P(Z>1)\\\\=1-P(Z$

Thus, the probability that a randomly selected passenger car gets more than 37.3 mpg is 0.1587.

7 0

3 years ago