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tangare [24]
3 years ago
10

The price of a computer was marked up by 50% and then marked down by 50%.

Mathematics
2 answers:
natita [175]3 years ago
5 0

Answer:

James is wrong because if you increase something's price by 50%, and decrease it by 50% of the new price, it will be lower than the original price.

Step-by-step explanation:

Let's say that the computer's price is around $1,000.

Since we have to mark it up by 50%, we have to turn this into a decimal and multiply that decimal by the original price. Then add the product to the original price

0.5 x 1,000 = 500

500 + 1,000 = 1,500

The marked up price of the computer is $1,500, then reduce it by 50%, do the same process as the first step but don't add it to the original price this time.

0.5 x 1,500 = 750

The computer's final price is $750

dalvyx [7]3 years ago
4 0

Answer:

percent change = 25% (drop)

Step-by-step explanation:

James reasoning is incorrect

Let the original price of the computer = $1000

If the computer was marked up by 50% then 1000 x 1.5 = $1500

If the computer was then marked down by 50% then 1500 x 0.5 = $750

Percent change = [ (difference between final value and initial value) ÷ initial value] x 100

= [ (1000 - 750) ÷ 1000 ] x 100

= 25% (drop)

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Find sin(a+b) if tan(a)=7/24 where a is in the third quadrant
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The complete question in the attached figure

we have that
tan a=7/24    a----> III quadrant
cos b=-12/13   b----> II quadrant
sin (a+b)=?

we know that
sin(a + b) = sin(a)cos(b) + cos(a)sin(b<span>)
</span>
step 1
find sin b
sin²b+cos²b=1------> sin²b=1-cos²b----> 1-(144/169)---> 25/169
sin b=5/13------> is positive because b belong to the II quadrant

step 2
Find sin a and cos a
tan a=7/24
tan a=sin a /cos a-------> sin a=tan a*cos a-----> sin a=(7/24)*cos a
sin a=(7/24)*cos a------> sin²a=(49/576)*cos²a-----> equation 1
sin²a=1-cos²a------> equation 2
equals 1 and 2
(49/576)*cos²a=1-cos²a---> cos²a*[1+(49/576)]=1----> cos²a*[625/576]=1
cos²a=576/625------> cos a=-24/25----> is negative because a belong to III quadrant
cos a=-24/25
sin²a=1-cos²a-----> 1-(576/625)----> sin²a=49/625
sin a=-7/25-----> is negative because a belong to III quadrant

step 3
find sin (a+b)
sin(a + b) = sin(a)cos(b) + cos(a)sin(b)
sin a=-7/25
cos a=-24/25
sin b=5/13
cos b=-12/13
so
sin (a+b)=[-7/25]*[-12/13]+[-24/25]*[5/13]----> [84/325]+[-120/325]
sin (a+b)=-36/325

the answer is
sin (a+b)=-36/325

8 0
3 years ago
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