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melisa1 [442]
3 years ago
7

I will give brainliest away if you solve this for me please.

Mathematics
2 answers:
Elis [28]3 years ago
8 0

Turn both equations into slope-intercept form [ y = mx + b ].

x + 3y = 3

~Subtract x to both sides

3y = 3 - x

~Divide 3 to everything

y = 1 - x/3

~Reorder

y = -1/3x + 1

4x + 3y = -6

~Subtract 4x to both sides

3y = -6 - 4x

~Divide 3 to everything

y = -2 - 4x/3

~Reorder

y = -4/3x - 2

Graph of the equations will be shown below. Note that the solution of graphing two equations will be where both equations intersect. Both lines intersect at (-3, 2), hence making that the solution.

Best of Luck!

diamong [38]3 years ago
5 0

Answer:

Hey, so this is what I got for them as equations. The 1st one is y=-1/3x+1, and the 2nd one is y=-4/3x-2.  Hope it helps

Step-by-step explanation:

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KATRIN_1 [288]

Answer:

Radius of the given circle is r = 2.

Step-by-step explanation:

Given equation of the circle is x^2 + y^2 = 4.

Now we need to find the radius of the given circle x^2 + y^2 = 4.

To find that let's compare with the formula of the circle with is x^2 + y^2 = r^2, where r is the radius.

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Two show your work questions
Svet_ta [14]

Answer:

x = 1; y = 1; z = 0

Step-by-step explanation:

First problem:

First equation minus second equation: 3y + 2z = 3      Eq. A

Second equation plus third equation: 2y + 4z = 2        Eq. B

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Answer: x = 1; y = 1; z = 0



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