All categories

3 years ago

Write the quadratic equation in standard form. (x - 3) 2 = 0

Mathematics

2 answers:

Pani-rosa [81]3 years ago

8 0

2 x -6 equals 0. add 6 to both sides. divide both sides by two. x equals 3

wolverine [178]3 years ago

7 0

2 x -6 equals 0 then add 6 to both sides then divide 2 by both sides then x=2

You might be interested in

Please help *THIS IS ON PERSONAL FINANCIAL LITERACY "

Crank

Answer:

I think the answer is $56,600

Step-by-step explanation:

I'm pretty sure you're just going to add $63,000+$8,400+$2,900+$1,1000. Then when you get a total of $75,400 and then I think you are going to subtract $15,400 from $75,400, you should get $60,000 then subtract $3,400 and you get $56,600.

7 0

3 years ago

Expand this question: 6(x - 4y)

user100 [1]

6x-24y is the answer

8 0

2 years ago

Justin bought a package of pens that contained one black one blue and one red pen he randomly pulled two pens out of the package

Nataly_w [17]

A:
black,blue
black,red
blue,red

B:
red,black
red,blue
red,green
black,blue
black,green
blue,green

5 0

3 years ago

Before the pandemic cancelled sports, a baseball team played home games in a stadium that holds up to 50,000 spectators. When ti

spayn [35]

Answer:

(a) $D(x)=-2,500x+60,000$

(b) $R(x)=60,000x-2500x^2$

(d)Optimal ticket price: $12

Maximum Revenue:$360,000

Step-by-step explanation:

The stadium holds up to 50,000 spectators.

When ticket prices were set at $12, the average attendance was 30,000.

When the ticket prices were on sale for $10, the average attendance was 35,000.

(a)The number of people that will buy tickets when they are priced at x dollars per ticket = D(x)

Since D(x) is a linear function of the form y=mx+b, we first find the slope using the points (12,30000) and (10,35000).

$\text{Slope, m}=\dfrac{30000-35000}{12-10}=-2500$

Therefore, we have:

$y=-2500x+b$

At point (12,30000)

$30000=-2500(12)+b\\b=30000+30000\\b=60000$

Therefore:

$D(x)=-2,500x+60,000$

(b)Revenue

$R(x)=x \cdot D(x) \implies R(x)=x(-2,500x+60,000)\\\\R(x)=60,000x-2500x^2$

(c)To find the critical values for R(x), we take the derivative and solve by setting it equal to zero.

$R(x)=60,000x-2500x^2\\R'(x)=60,000-5,000x\\60,000-5,000x=0\\60,000=5,000x\\x=12$

The critical value of R(x) is x=12.

(d)If the possible range of ticket prices (in dollars) is given by the interval [1,24]

Using the closed interval method, we evaluate R(x) at x=1, 12 and 24.

$R(x)=60,000x-2500x^2\\R(1)=60,000(1)-2500(1)^2=\$57,500\\R(12)=60,000(12)-2500(12)^2=\$360,000\\R(24)=60,000(24)-2500(24)^2=\$0$

Therefore:

Optimal ticket price:$12
Maximum Revenue:$360,000

3 0

3 years ago

Brianna wants to buy a digital camera for a photography class. One store offers the camera for $47 down and a payment plan of $2

denis-greek [22]

1.67 because if you calculate allof it thats your answer

5 0

3 years ago

Read 2 more answers