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2 years ago

10

Write the quadratic equation in standard form. (x - 3) 2 = 0

2 answers:

Pani-rosa [81]2 years ago

8 0

2 x -6 equals 0. add 6 to both sides. divide both sides by two. x equals 3

wolverine [178]2 years ago

7 0

2 x -6 equals 0 then add 6 to both sides then divide 2 by both sides then x=2

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If BD and EG are parallel lines and mBCF = 50°, what is mEFH?<br> Look at this diagram:

Burka [1]

It’s hard to tell due to no labels, but these are your angles due to the equal angles theorem and a few other theorems. Hopefully with this image you can hopefully find your answer. You may need to add angles together depending on what you are looking for. And possible even figure out what angle measure would make a (180 degree) triangle.
Hope this helped

4 0

2 years ago

Mr Coope drives 472 miles in 8 hours. At this rate, how many miles would he drive in 6

KatRina [158]

8hrs = 480mins
6hrs = 360 mins
472/480 = 0.983...
0.983... x 360 = 354
D) 354

6 0

2 years ago

A man buys a washing machine whose price VAT (value added Tax ) is Birr 175. lts VAT is charged at 15 % ,how much did the man ac

Ad libitum [116K]

9514 1404 393

Answer:

Birr 1341.67

Step-by-step explanation:

The tax is 15% of the price (p), so we have ...

0.15p = 175

p = 175/0.15 = 1166.67

When the tax is added, the total comes to ...

1166.67 +175 = 1341.67

The man actually paid Birr 1341.67.

5 0

3 years ago

A wind turbine is located at the top of a hill where the wind blows steadily at 12 m/s, and stands 37 m tall. The air then exits

marta [7]

Answer:

Power generated = 4.315 kW

Step-by-step explanation:

Given,

speed of wind when enters into the turbine, V = 12 m/s

speed of wind when exits from the turbine, U = 9 m/s

mass flow rate of the wind, m = 137 kg/s

According to the law of conservation of energy

Energy generated = change in kinetic energy

Since, the air is exiting at same elevation. So, we will consider only kinetic energy.

Energy generated in one second will be given by,

$E\ =\ \dfrac{1}{2}.mV^2-\dfrac{1}{2}.m.U^2$

$=\ \dfrac{1}{2}\times 137\times (12)^2-\dfrac{1}{2}\times 137\times (9)^2$

=4315.5 J

= 4.315 kJ

So, energy is generated in one second = 4.315 kJ

Power generated can be given by,

$P\ =\ \dfrac{\textrm{energy generated}}{time}$

And the energy is generated is already in per second so power generated will be 4.315 kW.

8 0

3 years ago

Simplify (2/9)^3<br> A.6/9<br> B.8/729<br> C.2/720

saw5 [17]

<u>Answer:</u>

$\frac{8}{729}$

<u>Explanation:</u>

Before we begin, remember that:

( $\frac{a}{b}$ )ⁿ = $\frac{a^n}{b^n}$

This means that power is distributed in case of division

The given is:

$(\frac{2}{9} )^3$

Applying the above rule, we would get:

$(\frac{2}{9} )^3$ = $\frac{2^3}{9^3} = \frac{2*2*2}{9*9*9} = \frac{8}{729}$

Hope this helps :)

8 0

3 years ago