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Leokris [45]
3 years ago
15

48m+42n choose 2 answers

Mathematics
1 answer:
Neporo4naja [7]3 years ago
8 0

Answer:

What is the question? Please write a question.

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The length of a rectangular room is one less than twice the width. The area of the room is 28 square feet. Find the dimensions o
Sholpan [36]

The first step to solve this problem is to represent variables for the width and the length:

Let w = width of the rectangle

      2w – 1 = length of the rectangle

The formula to compute for the area of the rectangle is:

A = LW

Substituting the values and variables to the formula:

28 = w (2w – 1)

2w^2 – w = 28

2w^2 – w – 28 = 0

Solve the quadratic equation:

(2w + 7)(w – 4) = 0

w = -7/2 or w = 4

You cannot use the -7/2 because there is no negative measurement.

W = 4 feet

L = 2(4) – 1 = 7 feet

Therefore the dimension of the rectangle is 4 feet by 7 feet.

7 0
3 years ago
Read 2 more answers
2x2=<br><br> what is the answer to this question?
posledela

Answer:

2×2=4

Step-by-step explanation:

...................

4 0
3 years ago
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Grafica y obten la ecuacion general de la circunferencia de centro y radio dados
Gelneren [198K]

Answer:

sorry I don't understand, I'm unable to read Spanish

5 0
3 years ago
Asking again since no one answered! I really need help :(
V125BC [204]

Answer:

P = 80

Step-by-step explanation:

The formula for P when only d is known is P=2√2*d so 2√2 * 20√2 = 80

5 0
3 years ago
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12) F(x)=(1/2) x;g(x)=(1/2)x+4
Luba_88 [7]
If this is asking for a transformation from f(x) to g(x), then the answer for this is 4 units up
5 0
3 years ago
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