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Rashid [163]
3 years ago
14

2x2= what is the answer to this question?

Mathematics
2 answers:
drek231 [11]3 years ago
5 0

Answer:

2x2=4

Solution:

This question is the type of question, where the 2x2 can basically also be a 2+2 and get the same answer. But, any ways, if we do 2x1, then, we get 2, and if we get 2x2, then we just have to do the double of two, which is four.

Final Answer:

2x2=4

Multiply 2 and 2 and get 4.

Thanks:

Thank you, please mark me the brainliest!

posledela3 years ago
4 0

Answer:

2×2=4

Step-by-step explanation:

...................

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Raina must choose a number between 55 and 101 that is a multiple of 2, 8 and 10. Write all the numbers that she could choose. If
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The only possible number is 80.

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The number in question needs to be a multiple of all three of 2, 8, and 10. As a result, it must also be a multiple of the least common multiplier (lcm) of the three number.

Start by finding the least common multiplier of the three numbers.

Factor each number into its prime components:

  • 2 is a prime number itself.
  • 8 = 2^3.
  • 10 = 2 \times 5.

The only prime factors are 2 and 5.

  • The greatest power of 2 among the three numbers is 3.
  • The greatest power of 5 among the three numbers is 1.

Therefore, the least common multiplier of the three number should be the product of 2^3 and 5. That's equal to 2^3 \times 5 = 8 \times 5 = 40.

In other words, the number (or numbers) in question could be written in the form 40\, k, where k is an integer.

The question requires that this number be between 55 and 101. In other words,

55 \le 40\, k \le 101.

The goal is to find the possible values of k. Note that from integer division by 40,

  • 55 = 1 \times 40 + 15, and
  • 101 = 2 \times 40 + 21.

The inequality becomes:

1 \times 40 + 15 \le 40\, k \le 2 \times 40 + 21.

However,

  • 1 \times 40 < 55 = 1 \times 40 + 15, and
  • 2 \times 40 + 21 = 101 < 3 \times 40.

Hence,

1 \times 40 < 1\times 40 + 15 \le 40\, k \le 2 \times 40 + 21 < 3 \times 40.

1 \times 40 < 40\, k < 3 \times 40.

Divide by the positive number 40 to obtain:

1 < k < 3.

Since k is an integers, k = 2.

Indeed, 40 \, k = 80 is between 55 and 101.

Therefore, 80 is the number in question.

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