Answer:
7. one triangle
8. two triangles
Step-by-step explanation:
When you are given two sides and one of the opposite angles, you can make a determination as follows:
- If the given angle is <em>opposite the longest given side</em>, there is one solution.
- If the given angle is <em>opposite the shortest given side</em>, there may be 0, 1, or 2 solutions.
For the latter case, the possibilities for sides b, c, and angle C are ...
C > 90° . . . . . . . . no solution
(b/c)sin(C) > 1 . . . no solution
(b/c)sin(C) = 1 . . . 1 solution
(b/c)sin(C) < 1 . . . 2 solutions
(The expression (b/c)sin(C) gives sin(B), so the value must lie within the range of the sine function in order for there to be any solution.)
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7. The given angle is opposite the <em>longest</em> given side. There is one solution.
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8. The given angle is opposite the <em>shortest</em> given side, so we compute
(b/c)sin(C) = (34/28)sin(20°) ≈ 0.41
This is less than 1, so there are two solutions.
Your question is: The perimeter of a rectangle is 60 meters. What are the possible lengths of any of the rectangle’s sides if its area exceeds 216 square meters?
The answer would be (12,18)
Answer:
2 decimal places
Step-by-step explanation:
just simple count the number of decimal points on both sides
3/5 divied by 1 5/9
3/5 times 9/14 =27/70
It already is simplified, youre answer is 27/70