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Paha777 [63]
3 years ago
14

Use the binomial theorem and multiplication to expand (1- x^2)(2-3x)^3​

Mathematics
1 answer:
madam [21]3 years ago
5 0

Answer:

(1-x2)× (2-3x)2

(1-x2) ×(8-36x+54x2-27x3)

8-36x+54x2-27x3-8x2+36x3-54x4+27x5

8-36x+46x2+9x3-54x4+27x5

Answer: 27x5-54x4+9x3+46x2-36x+8  

Step-by-step explanation:

step 1- expand the expression

step 2- remove the parentheses

step 3- collect like terms

step 4- reorder the terms

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Need help to answer question
Elena-2011 [213]

c iiiiiiiiiiiiiiiiiiiiiiiiiiiiii

3 0
3 years ago
Jane’s buying clothes. She can get 5 shirts & 4 sweaters for $229 or she can get 2 shirts & 3 sweaters for $128. How muc
makkiz [27]

Cost of 1 shirt is \$25 and cost of one sweater is \$26

<u>Solution: </u>

Given that  Jane’s buying clothes.

She can get 5 shirts & 4 sweaters for \$229

She can get 2 shirts & 3 sweaters for \$128

Need to determine cost of 1 shirt and 1 sweater.

Let assume cost of 1 shirt = \$x

And assume cost of 1 sweater = \$y

Let us create equations from give conditions

First condition is Cost of 5 shirt + cost of 4 sweater = \$229

\begin{array}{l}{\text { cost of 5 shirts }=5 \times \text { cost of 1 shirt }=5 \times x=5 x} \\\\ {\text { cost of 4 sweater }=4 \times \text { cost of 1 sweater }=4 \times y=4 y}\end{array}

So using first condition equation which we get is as follows

5 x+4 y=229 \rightarrow (1)

Second condition is Cost of 5 shirt + cost of 4 sweater = \$128

\begin{array}{c}{\text { cost of } 2 \text { shirts }=2 \times \text { cost of } 1 \text { shirt }=2 \times x=2 x} \\\\ {\text { cost of } 3 \text { sweater }=3 \times \text { cost of } 1 \text { sweater }=3 \times y=3 y}\end{array}

So using second condition equation which we get is as follows

2 \mathrm{x}+3 \mathrm{y}=128\quad\rightarrow (2)

Now we have two equations to be solved

\begin{array}{l}{5 x+4 y=229 \rightarrow (1)} \\\\ {2 x+3 y=128 \rightarrow (2)}\end{array}

On multiplying equation (1) by 2 and equation (2) by 5 to make coefficients of x equal in both equations, we get

\begin{array}{l}{2 x(5 x+4 y)=2\times 229} \\\\ {10 x+8 y=458 \rightarrow (3)} \\\\ {5 x(2 x+3 y)=5 \times 128} \\\\ {10 x+15 y=640 \rightarrow (4)}\end{array}

On subtracting (3) from (4), we get

\begin{array}{l}{(10 \mathrm{x}-10 \mathrm{x})+(15 \mathrm{y}-8 \mathrm{y})=640-458} \\\\ {\Rightarrow 7 \mathrm{y}=182} \\\\ {\Rightarrow \mathrm{y}=\frac{182}{7}=26}\end{array}

On substituting y = 26 in equation (1) we get

\begin{array}{l}{\Rightarrow 5 \mathrm{x}+(4 \times 26)=229} \\\\ {\Rightarrow 5 \mathrm{x}=229-104} \\\\ {\Rightarrow 5 \mathrm{x}=125} \\\\ {\Rightarrow \mathrm{x}=\frac{125}{5}=25}\end{array}

Cost of 1 shirt = \$x = \$25

Cost of 1 sweater = \$y = \$26  

7 0
3 years ago
Find the distance between to points given?
kondor19780726 [428]
<h3>Answer:  29 goes in the box</h3>

===============================================

Explanation:

The two endpoints are (-3,1) and (-1,-4)

Apply the distance formula

d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(-3-(-1))^2 + (1-(-4))^2}\\\\d = \sqrt{(-3+1)^2 + (1+4)^2}\\\\d = \sqrt{(-2)^2 + (5)^2}\\\\d = \sqrt{4 + 25}\\\\d = \sqrt{29}\\\\d \approx 5.3851648\\\\

So the approximate distance is roughly 5.38 units and the exact distance is \sqrt{29} units.

--------------

As a slight alternative, you can plot the point (-3,-4) and draw a right triangle. Then apply the pythagorean theorem to find the length of the hypotenuse. The vertical and horizontal legs are 5 and 2 units respectively.

It turns out that the distance formula is essentially a modified form of the pythagorean theorem.

5 0
3 years ago
identify the solution of the equation x divided by 7 equals 3: 20,21,20 btw this is middle school work. :)
Marrrta [24]

Answer:

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Step-by-step explanation:

7 0
3 years ago
For f(x)=2x+1 and g(x) =x2-7, find (f*g)(x)
Vadim26 [7]

Answer:

  (f×g)(x) = 2x³ +x² -14x -7

Step-by-step explanation:

(f×g)(x) = f(x)×g(x) = (2x +1)×(x² -7)

  = 2x(x² -7) +1(x² -7)

  = 2x³ -14x +x² -7

(f×g)(x) = 2x³ +x² -14x -7

3 0
3 years ago
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