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3 years ago

For f(x)=2x+1 and g(x) =x2-7, find (f*g)(x)

Mathematics

1 answer:

Vadim26 [7]3 years ago

3 0

Answer:

(f×g)(x) = 2x³ +x² -14x -7

Step-by-step explanation:

(f×g)(x) = f(x)×g(x) = (2x +1)×(x² -7)

= 2x(x² -7) +1(x² -7)

= 2x³ -14x +x² -7

(f×g)(x) = 2x³ +x² -14x -7

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3 years ago

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klemol [59]

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Step-by-step explanation:

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2 years ago

Create the equation of a quadratic function with a vertex of (5,6) and a y-intercept of -69

Elena L [17]

If the y-intercept is at -69, meaning the point is (0, -69), thus x = 0, y = -69

$\bf ~~~~~~\textit{parabola vertex form}
\\\\
\begin{array}{llll}
\boxed{y=a(x- h)^2+ k}\\\\
x=a(y- k)^2+ h
\end{array}
\qquad\qquad
vertex~~(\stackrel{}{ h},\stackrel{}{ k})\\\\
-------------------------------\\\\
vertex~(5,6)\quad 
\begin{cases}
x=5\\
y=6
\end{cases}\implies y=a(x-5)^2+6
\\\\\\
\textit{we also know that }
\begin{cases}
x=0\\
y=-69
\end{cases}\implies -69=a(0-5)^2+6
\\\\\\
-75=25a\implies \cfrac{-75}{25}=a\implies a=-3
\\\\\\
therefore\qquad \boxed{y=-3(x-5)^2+6}$

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2 years ago