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blondinia [14]
3 years ago
13

19. A cylinder with a radius of 0.28 m and

Mathematics
2 answers:
alexgriva [62]3 years ago
8 0

Answer: Mark me brainliest..

Step-by-step explanation: and imma put the answer inside the comments if you do so. youve got nothing to lose! :D

Dafna11 [192]3 years ago
6 0

Answer:

0.26

Step-by-step explanation:

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Find the domain of the following functions ?
jeka57 [31]

Answer:

A) x ≠ 0

B) x ≠ 3

Step-by-step explanation:

The domain is all the possible values of x such that f(x) exists.

A) f(x) = (x + 5) / x

x can't be 0 (can't divide by 0), so the domain of x is all values other than 0.

You can write this in interval notation:

(-∞, 0)⋃(0, ∞)

Inequality notation:

x < 0 or x > 0

Or simply:

x ≠ 0

B) f(x) = 1 / (x - 3)

x can't be 3 (can't divide by 0), so the domain of x is all values other than 3.

(-∞, 3)⋃(3, ∞)

x < 3 or x > 3

x ≠ 3

6 0
3 years ago
Jack needs 22 pirate for every two pirate ships he Manages
solniwko [45]

Answer:

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Step-by-step explanation:

3 0
3 years ago
A circle has a circumference of 907.46907.46907, point, 46 units. What is the diameter of the circle? units
Ilya [14]
The answer is 289units
8 0
4 years ago
3kg 250g: 5kg pls tell me the answer I have exams
larisa86 [58]

Answer:

Well if it made sense..

Step-by-step explanation:

3 0
3 years ago
Angle θ is in standard position. If (8, -15) is on the terminal ray of angle θ, find the values of the trigonometric functions.
notsponge [240]

ANSWER

\sin( \theta)   =  -  \frac{15}{17}

\csc( \theta)   =  -  \frac{17}{15}

\cos( \theta)   =   \frac{8}{17}

\sec( \theta)   =    \frac{17}{8}

\tan( \theta)   =  -  \frac{15}{8}

\cot( \theta)   =  -  \frac{8}{15}

EXPLANATION

From the Pythagoras Theorem, the hypotenuse can be found.

{h}^{2}  = 1 {5}^{2}  +  {8}^{2}

{h}^{2}  = 289

h =  \sqrt{289}

h = 17

The sine ratio is negative in the fourth quadrant.

\sin( \theta)  = -   \frac{opposite}{hypotenuse}

\sin( \theta)   =  -  \frac{15}{17}

The cosecant ratio is the reciprocal of the sine ratio.

\csc( \theta)   =  -  \frac{17}{15}

The cosine ratio is positive in the fourth quadrant.

\cos( \theta)   =  \frac{adjacent}{hypotenuse}

\cos( \theta)   =   \frac{8}{17}

The secant ratio is the reciprocal of the cosine ratio.

\sec( \theta)   =    \frac{17}{8}

The tangent ratio is negative in the fourth quadrant.

\tan( \theta)   =  -  \frac{opposite}{adjacent}

\tan( \theta)   =  -  \frac{15}{8}

The reciprocal of the tangent ratio is the cotangent ratio

\cot( \theta)   =  -  \frac{8}{15}

8 0
3 years ago
Read 2 more answers
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