Answer:
C. It is a male with atleast one dominant allele
Explanation:
In the given pedigree, the two normal parents of the generation I have one daughter with the attached earlobe. Since the trait is recessive, the daughter should be homozygous recessive to express the trait. The genotype of the daughter (shaded circle in generation II) is "aa". To have a daughter with "aa" genotype, both the parents should have one copy of "a" allele. So, the genotype of both parents is "Aa".
In generation II, individual A is non-shaded square. Squares represent males in a pedigree. Since its not shaded, it does not have attached earlobe. Both the parents are heterozygous dominant for attached earlobes (Aa x Aa = 1/4 AA : 1/2 Aa : 1/4 aa). The genotype of this individual may be AA or Aa.
Over a liter of water is reabsorbed by the colon
LINKAGE
Independent assortment refers to the allele segregation of two different genes. They are expected to be segregated from each other independently.This is not seen in monohybrids, they are usually heterozygous for an allelic pair only. Link genes cannot assort independently. These are inherited together during meiosis phase of sexual reproduction. Usually genes that are close together will tend to stick together resulting into inheritance of genes as pairs.
